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3 years ago

20% of 57 is what number ? The proportion is ?

Mathematics

1 answer:

Elanso [62]3 years ago

6 0

Answer:

11.4

20/100 = x/57

Step-by-step explanation:

It is perhaps simplest just to translate the given English sentence into a mathematical sentence.

... 20% ... ... of ... 57 ... is ... what number

... 20/100 ... × ... 57 .... = ... what number . . . . . . . . translation to math sentence

... 11.4 = what number . . . . . . . . carry out the multiplication

_____

If you're asked to write this as a proportion, you can write it like this:

$\dfrac{20}{100}=\dfrac{\text{what number}}{57}$

You can solve this proportion by multiplying by 57 (the denominator under "what number"). Doing so gives you the same arithmetic sentence as shown above.

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2x + 4y = 12 and y = -1/2x + 3

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In an experiment, a variable, position-dependent force F(x) is exerted on a block of mass 1.0kg that is moving on a horizontal s

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Answer: correct option is C

The function F(x) for 0 < x < 5, the block's initial velocity, and the value of Ff.

Step-by-step explanation:

The total work done = P.E + K.E

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The speed V depends on the position:

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The Sydney Morning Herald - February 8, 2004 reported that in 1961, the average number of children born to Australian women (3.5

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Answer:

<h2>A. Agree, 4 children is the most typical number of children.</h2>

Step-by-step explanation:

By analysis the problem, we can make our decision by first determining the percent of 3.55 of 4

therefore the percentage can be computed as

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The set of points (-3, 4), (-1, 1), (-3,-2), and (-5,1) identifies the vertices of a quadrilateral. Which is the most specific d

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Answer:

Option (4). Rhombus

Step-by-step explanation:

From the figure attached,

Distance AB = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

= $\sqrt{(1-4)^2+(-5+3)^2}$

= $\sqrt{(-3)^2+(-2)^2}$

= $\sqrt{13}$

Distance BC = $\sqrt{(4-1)^2+(-3+1)^2}$

= $\sqrt{9+4}$

= $\sqrt{13}$

Distance CD = $\sqrt{(-2-1)^2+(-3+1)^2}$

= $\sqrt{9+4}$

= $\sqrt{13}$

Distance AD = $\sqrt{(1+2)^2+(-5+3)^2}$

= $\sqrt{9+4}$

= $\sqrt{13}$

Slope of AB ( $m_{1}$ ) = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

= $\frac{4-1}{-3+5}$

= $\frac{3}{2}$

Slope of BC ( $m_{2}$ ) = $\frac{4-1}{-3+1}$

= $-\frac{3}{2}$

If AB and BC are perpendicular then,

$m_{1}\times m_{2}=-1$

But it's not true.

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It shows that the consecutive sides of the quadrilateral are not perpendicular.

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Slope of diagonal BD = $\frac{4+2}{-3+3}$

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Therefore, both the diagonals AC and BD will be perpendicular.

And the quadrilateral formed by the given points will be a rhombus.

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3 years ago

Answer this question <br> Percent: increase / decrease

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Find .5% of 1.8 meters
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It’s increases by .09meters
Add that to the 1.8 meter bar
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