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3 years ago

Compare the decimals 117.93 and 117.859.

Mathematics

1 answer:

LiRa [457]3 years ago

3 0

You need to see which is more

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What is the product of (3a + 2)(4a? - 2a + 9)?

yan [13]

Answer:

The answer is 12a^3+2a²+23a+18 ....

Step-by-step explanation:

The given terms are:

(3a + 2)(4a² - 2a + 9)

Now multiply each value of second bracket with the first bracket:

=4a²(3a+2) -2a(3a+2)+9(3a+2)

=12a^3+8a²-6a²-4a+27a+18

Solve the like terms:

=12a^3+2a²+23a+18

Therefore the answer is 12a^3+2a²+23a+18 ....

4 0

3 years ago

PLEASE ASAP ILL GIVE BRAINLIEST.

kaheart [24]

I’m going to say the top one it seems like that would be correct

6 0

2 years ago

Read 2 more answers

The two figures above are congruent. Find the measure of the angle that isn't labeled on either figure.

harkovskaia [24]

Answer:Idk sry

Step-by-step explanation:

7 0

3 years ago

Help me i need help asap

olganol [36]

Answer:

6.5

Step-by-step explanation:

when a negative is multiplied by a negative it in turns turns into a positive...hence 2+4.5

6 0

2 years ago

A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Lyrx [107]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

3 0

3 years ago