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yawa3891 [41]
3 years ago
9

Compare the decimals 117.93 and 117.859.

Mathematics
1 answer:
LiRa [457]3 years ago
3 0
You need to see which is more

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Solve the equation for y.<br> 8x – 9y = 11
pav-90 [236]
8x-9y=11

First you move the 8x because you have to leave the 9y alone

8x-9y=11
-8x        -8x

-9y=11-8x

Now you have to move the -9, so the inverse of multiplying is dividing so you divide -9.

-9y/-9= 11/-9 -8x/-9

since you can't have negative as a denominator it would be:

y= -11/9+8x/9

<span>You have to change the signs</span>
3 0
3 years ago
Write two different expressions to represent the sale price of a fishing pole, f, after a 20% discount.
Rom4ik [11]

Answer:

When we have a discount of X% of the original price, the new price is calculated as:

New price = (original price) - (original price)*(X%/100%)

In our case, let's define:

P = original price of the fishing pole

f = price of the fishing pole after the discount

X% = 20%

Then the equation for the price of the fishing pole is:

f = P - P*(20%/100%) = P - P*0.2 = P*(1 - 0.2) = P*0.8

f = 0.8*P

This means that the price after the discount is 0.8 times the original price.

7 0
3 years ago
The product of 8 and b is less than or equal to 13
Ugo [173]

Answer:

1 or 0

Step-by-step explanation:

8 x b = 13

You can't divide 8 by two because that equals 16 so 8 x 1 is less than 8.

And 8 x 0 is 0

7 0
3 years ago
Total blood cholesterol level was measured for each of
laiz [17]
<h3>Answer: Mean = 218.9.</h3><h3>Median = 229</h3><h3>Mode = Zero mode.</h3>

Step-by-step explanation:

Given blood cholesterol level was measured for each of 8 adults (in mg/dL) are:

264, 191, 160, 148, 262, 212, 268, 246

In order to find the mean, we need to add all those 8 numbers and divide by 8.

Therefore, mean = \frac{264+191+160+148+262+212+268+246}{8} =\frac{1751}{8} =218.9.

<h3>Mean = 218.9.</h3>

In order to find the median, we need to arrange them in ascending order:

148, 160, 191, 212, 246, 262, 264, 268.

The middle most two values are 212 and  246.

Therefore, median = \frac{212+246}{2} =\frac{458}{2} = 229.

<h3>Median = 229.</h3>

\mathrm{The\:mode\:is\:the\:term\:in\:the\:data\:set\:that\:appears\:the\:most.}

\mathrm{If\:there\:is\:more\:than\:one\:term\:that\:appears\:the\:most,\:then\:there\:is\:no\:mode.}

\mathrm{Count\:the\:number\:of\:times\:each\:element\:appears\:in\:the\:list}

\begin{pmatrix}148&160&191&212&246&262&264&268\\ 1&1&1&1&1&1&1&1\end{pmatrix}

\mathrm{The\:most\:common\:element\:is\:not\:unique,\:so\:there\:is\:no\:mode}

<h3>Therefore, Mode = Zero mode.</h3>
5 0
3 years ago
Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}
miskamm [114]

Answer:

-3+i\sqrt{3} , 1+\sqrt{3}

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

\alpha = x+iy\\\beta = x-iy

since they are conjugates

\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}

\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}

Imaginary part of the above =0

i.e. \sqrt{3} (x^2-3)+2x\sqrt{3} =0\\x^2+2x-3=0\\(x+3)(x-1) =0\\x=-3,1

So the value of alpha = -3+i\sqrt{3} , 1+\sqrt{3}

3 0
3 years ago
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