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3 years ago

Solve the following equation for the variable x. ( 1/27 is a fraction )

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

5 0

The answer is,
$\frac{10935}{59048}$
Also equivalent to about, 0.185188.

Masja [62]3 years ago

4 0

<span>3^(4x-5) =(1/27)^2x+10
</span>3^(4x-5) =(3^-3)^(2x+10)
3^(4x-5) =3^(-6x-30)
4x - 5 = -6x - 30
10x = -25
x = -2.5

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If you have two nickels and two dimes and nine pennies how much will that be

Drupady [299]

39cents would be the answer

8 0

3 years ago

Do you agree with the researchers method of predicting the population? Why or why not?

Burka [1]

Yes, I agree with the researcher's method. All the values of $a_{n}$ in the table correspond to the values of n by using their formula.

Step-by-step explanation:

Step 1:

If we substitute the values of n in the researcher's equation and we get the right values of $a_{n}$ , we can agree with the researcher's method.

The researcher's formula is $a_{n} = 1000(2)^{n-1}.$ Here $a_{n}$ is the wombat population and n is the number of years.

Step 2:

When n = 1, $a_{1} = 1000(2)^{1-1} = 1000(1) = 1,000,$

when n = 2, $a_{2} = 1000(2)^{2-1} = 1000(2) = 2,000,$

when n = 3, $a_{3} = 1000(2)^{3-1} = 1000(4) = 4,000,$

when n = 4, $a_{4} = 1000(2)^{4-1} = 1000(8) = 8,000,$

when n = 5, $a_{5} = 1000(2)^{5-1} = 1000(16) = 16,000.$

As all the values correspond to the values on the table, I agree with the researcher's method.

6 0

3 years ago

Find the distance between -23 and 17 on a number line.<br> d =

Svet_ta [14]

Answer:

Distance between -23 & 17 = 40

Step-by-step explanation:

6 0

3 years ago

(x^2−1)(3x−4)(3x+4) what is the product

Andrei [34K]

Answer:

9x^4-25x^2+16

Step-by-step explanation:

(x^2−1)(3x−4)(3x+4)=(*)

(x^2−1)((3x)^2−4^2) =

(x^2 - 1)(9x^2-16)=

x^2*9x^2 - x^2*16 - 1*9x^2 +16=

9x^4-16x^2-9x^2+16=

9x^4-25x^2+16

(*) (A-B)(A+B) =A^2 - B^2

6 0

3 years ago

Simplify 36x^4 42x^7

Alja [10]

The first step to simplify this equation is to multiply the numbers
1512 $x^{4}$ × $x^{7}$
next,, youll multiply the terms with the same base by adding their exponents
1512 $x^{4+7}$
finally,, youll add the numbers together
1512 $x^{11}$
since you cant simplify any further,, the correct answer to your question is 1512 $x^{11}$
let me know if you have any further questions
:)

4 0

3 years ago