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3 years ago

15

PLZ HELPPPPP

1 answer:

QveST [7]3 years ago

4 0

Use the quadratic formula with a = 2, b = -5, and c = 1

x = -b ± sq rt b2 - 4ac
-------------------- <---------- Please note: sq rt is over entire expression of b^2 - 4ac
2a

x = - (-5) ± sq rt (-5)2 + 4(2)(1)
-------------------------------- <---------Please note: sq rt is over entire expression (-5)2 + 4(2)(1)
2(2)

x = 5 ± √17
---------
4

x = 5 + 1√17 OR x = 5 + -1√17
--- --- --- ----
4 4 4 4

Answer: x = 5 + 1√17 OR x = 5 + -1√17
--- -- -- --
4 4 4 4

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We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

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By the same logic, we have that:

$B = b + (A \cap B)$

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This means that $A \cap B = 0.5$

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This means that $B = 0.6$

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B) he wins exactly one race.

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There is a 30% probability that he wins exactly one race.

C) he wins neither race

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From a), we have that there is an 80% probability that he wins at least one race.

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