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4 years ago

Help on 3, 4 and 5 !!

Mathematics

1 answer:

MAVERICK [17]4 years ago

6 0

3.c
4.c
5.b
3 and 5 are factoring and you should learn to do it.
4 is simplifying
to factor use FOIL its an acronym and it would be easier if you look up a video on youtube for it
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Donna has a checking account that charges $0.15 for each check written and

Mama L [17]

The formular which can be used to obtain the monthly charges as a function of the number of cheques written is 9.75 + 0.15x

Charges on account :

Charge per check written = $0.15
Monthly services charge = $9.75

The total amount charged monthly, F as a function of the number of cheques written, x can be expressed thus :

Monthly service charge + (charge per check × number of cheques written)

F(x) = 9.75 + 0.15x

Therefore, the charge function which can be used to calculate the total monthly charge on his account ls F(x) = 9.75 + 0.15x

Learn more : brainly.com/question/18405415

3 0

2 years ago

In 2003, the price of a certain automobile was approximately $32,000 with a depreciation of $1,740 per year. After how many year

IRINA_888 [86]

Answer:

The correct answer is 5 years i.e. 2008.

Step-by-step explanation:

Price of the automobile in 2003 is $32000.

Depreciation per year is given by $1740.

Therefore let the car value is depreciated for t number of years.

Value depreciated for t years is given by $ (1740t).

The final value of the car after t years is given to be $23300.

Thus the equation is given by 32000 - 1740t = 23300.

⇒ 1740t = 32000 - 23300

⇒ 1740t = 8700

⇒ t = 5

Thus after 5 years the value of the car is $23300.

Thus in 2008 the depreciated price of the car would be $23300.

7 0

4 years ago

An experiment consists of drawing a marble out of a bag, observing the color, and then placing it back in the bag. Suppose the e

Elan Coil [88]

The experimental data suggest that

$\mathbb P(\text{red})\approx\dfrac{38}{75}$
$\mathbb P(\text{blue})\approx\dfrac{23}{75}$
$\mathbb P(\text{green})\approx\dfrac{11}{75}$
$\mathbb P(\text{yellow})\approx\dfrac3{75}$

Because the marble is replaced after being drawn, and so the number of marbles of a given color remains the same, the event of drawing any given color is independent of what was drawn before. So

$\mathbb P(\text{2 consecutive yellows})\approx\dfrac3{75}\cdot\dfrac3{75}=\dfrac1{625}$

5 0

4 years ago

Read 2 more answers

Problem 2.191 A researcher receives 93 containers of oxygen. Of those containers, 20 have oxygen that is not ionized and the res

Ahat [919]

Answer:

Step-by-step explanation:

Given that there are 20 non ionized containers and 73 ionized containers

Two samples are drawn without replacement

a) the probability that the first one selected is not ionized= $\frac{20}{93} =0.215$