The width is 146.0315533981 cuz 12033÷82.4 is 146.0315533981
Answer:
x<5/2
Step-by-step explanation:
hope this helps :)
Answer:g is greater than or equal to 6g + 18/5, or g >_ 6g + 18/5
Step-by-step explanation: 5G- 2 <_ 6g + 16
Add 2 to the 16. 5g <_ 6g + 18.
Divide 5 to both sides. g >_ 6g + 18/5
We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.
Since 200 km is "halfway", the total distance must be 400 km.
time = distance / speed
total time = (time for first half) + (delay) + (time for second half)
400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40
The speed of the bus before the traffic holdup was 40 km/h.
