18 +2 = 20
s = 20
Hope This Helps You!
Good Luck Studying :)
We are asked to find the proportion of sugar to number of cookies
Sugar = 200g
Number of cookies = 48
proportion of sugar to cookies = 200 : 48
how many cookies he can make with 350 grams of sugar?
let x = number of cookies
proportion of sugar to cookies = 350 : x
equate the <em>proportions</em>
200 : 48 = 350 : x
200/48 = 350/x
cross product
200 × x = 350 × 48
200x = 16800
x = 16800/200
x = 84 cookies
find the number of cookies, y, Ezra can make with x grams of sugar?
y = grams of sugar, x / number of cookies
y = 350/84
y = 4.17x
Therefore,
Ezra can make 84 cookies with 350 grams of sugar
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brainly.com/question/3796978
Dudjhcbwerjhgfbsrfcbhfhsdgvvhjsfvvsrfjhgvbjysrfbgrbvhjsrgfbvygsrfr sorry
Answer:
x = -2
Step-by-step explanation:
![f(x) =x^2 -2x\:\: and \:\: g(x) = 6x + 4\\(f+g)(x) = f(x) + g(x) \\(f+g)(x) = x^2 -2x+ 6x + 4\\(f+g)(x) = x^2+4x + 4\\(f+g)(x) = (x+2)^2\\ 0 = (x+2)^2...[\because (f+g)(x) =0]\\0 = x+2\\\therefore x = -2](https://tex.z-dn.net/?f=f%28x%29%20%3Dx%5E2%20-2x%5C%3A%5C%3A%20and%20%5C%3A%5C%3A%20g%28x%29%20%3D%206x%20%2B%204%5C%5C%28f%2Bg%29%28x%29%20%3D%20f%28x%29%20%2B%20g%28x%29%20%5C%5C%28f%2Bg%29%28x%29%20%3D%20x%5E2%20-2x%2B%206x%20%2B%204%5C%5C%28f%2Bg%29%28x%29%20%3D%20x%5E2%2B4x%20%2B%204%5C%5C%28f%2Bg%29%28x%29%20%3D%20%28x%2B2%29%5E2%5C%5C%200%20%3D%20%28x%2B2%29%5E2...%5B%5Cbecause%20%28f%2Bg%29%28x%29%20%3D0%5D%5C%5C0%20%3D%20x%2B2%5C%5C%5Ctherefore%20x%20%3D%20-2)
Check the picture below.
so, as I see it, we can simply move from the point P, 360° counter-clockwise, the green one, and we'll be landing on a positive angle on the 1st Quadrant, the angle of 360° + 30° = 390°.
we can also move 360° clockwise, the red one, from P, so we'll be landing at -360° + 30 = -330°, also on the 1st Quadrant, but a negative counterpart.
now, if we move by jumps of 360° on either direction, we'll be landing coterminal with P all the time, so if we use simply multiply 360° by "n", some integer, then that angle added or subtracted from 30°, will be coterminal with P.
( 6 , 30°±360n°) where n ∈ ℤ.