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3 years ago

15

Cheryl paid $37.20 for 12 gallons of ice cream for a school picnic. How much would 1 quart of ice cream cost?

2 answers:

mestny [16]3 years ago

8 0

.78 cents for one quart <--- Answer

First you need to find how much is it per gallon
$37.20/12= $3.10

Now we need to find out how many quarts are in a gallon. Which is 4 quarts per 1 gallon

Now that we know this you need to divide the chost of one gallon by 4(# of quarts in one gallon)
$3.10/4= .78 cents

Gnesinka [82]3 years ago

8 0

If you round 0.775 to the nearest cent, the answer is 0.78 I believe.

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3 years ago

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(a) Find parametric equations for the line through (1, 4, 4) that is perpendicular to the plane x − y + 2z = 7. (Use the paramet

Alex777 [14]

Answer:

$x=1+t\\y=4-t\\z=4+2t$

Step-by-step explanation:

A vector perpendicular to the plane ax+by+cz+d=0 is of the form $(a,b,c)$ .

So, a vector perpendicular to the plane x − y + 2z = 7 is $(1,-1,2)$ .

The parametric equations of a line through the point $(x_0,y_0,z_0)$ and parallel to the vector $(a,b,c)$ are as follows:

$x=x_0+at\\y=y_0+bt\\z=z_0+ct$

Put $(x_0,y_0,z_0)=(1,4,4)$ and $(a,b,c)=(1,-1,2)$

Therefore,

$x=1+t\\y=4-t\\z=4+2t$

xy-plane:

Put z = 0 ⇒ t = -2 ⇒x = - 1 , y = 6

So, at point (-1,6,0)

yz-plane:

Put x = 0 ⇒ t = -1 ⇒ y = 5, z =2

So, at point (0,5,2)

xz-plane:

Put y = 0 ⇒ t = 4 ⇒ x = 5, z = 12

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3 years ago

What is the sine value of π? <br> -1/2<br> 1/2<br> 0<br> 1

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sin( $\pi$ )=Sin( $\pi$ -0) =Sin 0=0

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3 years ago

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AfilCa [17]

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3 years ago

Assume that IQ scores are normally distributed with a mean of 100 and a standard deviation of 16. If 100 people are randomly sel

laiz [17]

Answer:

0.03 is the probability that for the sample mean IQ score is greater than 103.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 16

Sample size, n = 100

We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$\dfrac{\sigma}{\sqrt{n}} = \dfrac{16}{\sqrt{100}} = 1.6$

P( mean IQ score is greater than 103)

P(x > 103)

$P( x > 103) = P( z > \displaystyle\frac{103 - 100}{1.6}) = P(z > 1.875)$

$= 1 - P(z \leq 1.875)$

Calculation the value from standard normal z table, we have,

$P(x > 103) = 1 - 0.970 =0.03= 3\%$

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3 years ago