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Paul [167]
3 years ago
12

PLEASE ANSWER! DESPERATE, DONT KNOW HOW TO DO IT!

Mathematics
1 answer:
Annette [7]3 years ago
5 0

Answer:

a) x = -7

b) x = -3/2

c) x = -3/2

d) x = 2

e) x = -1

f) x = -2

g) x = 7/3

h) z = -18/5

i) x = 6

Explanation:

The are a couple of rules you should know first.

Negative exponent rule: a^{-x} = \frac{1}{a^{x}}

A negative exponent means the same thing as the positive exponent as a denominator under 1.

Exponent to another exponent: (a^{x})^{n}=a^{xn}

When raising an exponent to another exponent, you multiply the exponents.

Fraction as a base rule: (\frac{a}{b})^{x} = \frac{a^{x}}{b^{x}}

Apply the exponent to the numerator and denominator.

Base 1 rule: 1^{x} = 1

1 to the power of anything is 1.

Focus on exponents only: a^{x} = a^{n}\\x = n

If the bases are the same on both sides of the equation, you can solve for "x" in the exponent by focusing on it only.

Write as an exponent: Rewrite a normal number as an exponent instead. Example: 8=2^{3} or 125=5^{3}

Also, you need to know how to rearrange and simplify formulas to isolate variables (by doing reverse operations in reverse BEDMAS order).

Know how to use the distributive property with brackets, when you multiply each of the terms in the brackets with the term on the outside.

Use each of these rules to solve.

a) 2^{x+4} = \frac{1}{8}   Write 8 as exponent

2^{x+4} = \frac{1}{2^{3}}   Negative exponent rule

2^{x+4} = 2^{-3}   Focus on exponents only

x+4 = -3   Subtract 4 from each side to isolate

x = -3-4

x = -7

b) 9^{x}=\frac{1}{27}   Write 27 as exponent

9^{x}=\frac{1}{3^{3}}   Write 9 as exponent

(3^{2})^{x}=\frac{1}{3^{3}}   Exponent to another exponent

3^{2x}=\frac{1}{3^{3}}   Negative exponent rule

3^{2x}=3^{-3}   Focus on exponents only

2x=-3   Divide both sides by 2 to isolate

x=-\frac{3}{2}

c) 25^{x}=\frac{1}{125}   Rewrite 125 as exponent

25^{x}=\frac{1}{5^{3}}   Rewrite 25 as exponent

(5^{2})^{x}=\frac{1}{5^{3}}   Exponent to another exponent

5^{2x}=\frac{1}{5^{3}}   Negative exponent rule

5^{2x}=5^{-3}   Focus only exponents only

2x=-3   Divide both sides by 2 to isolate

x=-\frac{3}{2}

d)  7(3^{x})=63   Divide both sides by 7 to isolate

3^{x}=63/7

3^{x}=9   Write 9 as exponent

3^{x}=3^{2}   Focus on exponents

x=2

e) 10^{3x}=0.001   Write 0.001 as fraction

10^{3x}=\frac{1}{1000}   Write 1/1000 as exponent

10^{3x}=\frac{1}{10^{3}}   Neg. exponent

10^{3x}=10^{-3}   Focus on exponents

3x=-3   Divide both sides by -3

x=-3/3

x=-1

f) 6(\frac{1}{10})^{x}=600   Divide both sides by 6

(\frac{1}{10})^{x}=\frac{600}{6}

(\frac{1}{10})^{x}=100  Write 100 as exponent

(\frac{1}{10})^{x}=10^{2}   Fraction as base rule

\frac{1^{x}}{10^{x}}=10^{2}   Base 1 rule

\frac{1}{10^{x}}=10^{2}   Neg. exponent

10^{-x}=10^{2}   Focus on exponent

-x=2   Divide both sides by -1

x=-2

g) 27^{x-3}=(\frac{1}{3})^{2}   Write 27 as exponent

(3^{3})^{x-3}=(\frac{1}{3})^{2}   Exponent to another exponent

3^{3(x-3)}=(\frac{1}{3})^{2}   Fraction as base

3^{3(x-3)}=\frac{1^{2}}{3^{2}}   Base 1 rule

3^{3(x-3)}=\frac{1}{3^{2}}   Neg. exponent

3^{3(x-3)}=3^{-2}   Focus

3(x-3)=-2   Distribute over brackets

3x-9=-2   Add 9 to both sides

3x=-2+9

3x=7   Div. both sides by 3

x=\frac{7}{3}

h) 4^{\frac{2z}{3}} = 8^{z+2}   Write 4 as exponent

(2^{2})^{\frac{2z}{3}} = 8^{z+2}   Exponent to another exponent

2^{2\frac{2z}{3}} = 8^{z+2}   Write 8 as exponent

2^{2\frac{2z}{3}} = (2^{3})^{z+2}   Exponent to another exponent

2^{2\frac{2z}{3}} = 2^{3(z+2)}   Focus

2\frac{2z}{3} = 3(z+2)   Multiply whole number with fraction

\frac{4z}{3} = 3(z+2)   Distribute

\frac{4z}{3} = 3z+6   Multiply both sides by 3

4z = 3(3z+6)   Distribute

4z = 9z+18   Subtract 9z from both sides

4z-9z = 18

-5z = 18   Div. both sides by -5

z = -\frac{18}{5}

i) 5(2)^{x-1}+3=163   Subtract 3 on both sides

5(2)^{x-1}=163-3

5(2)^{x-1}=160   Div. both sides by 5

(2)^{x-1}=160/5

(2)^{x-1}=32   Write 32 as exponent

(2)^{x-1}=2^{5}   Focus

x-1=5   Add 1 to both sides

x=5+1

x=6

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4 years ago
Use the triangle shown to find m∠Q and m∠S.
Elodia [21]
<h2><u>Hope this helps :)</u></h2>

Step-by-step Example 1:

Two angles are supplementary. If the measure of the angle is twice the measure of the other, find the measure of each angle.

Let the measure of one of the supplementary angles be a .

Measure of the other angle is 2 times a .

So, measure of the other angle is 2a .

If the sum of the measures of two angles is 180° , then the angles are supplementary.

So, a+2a=180°

Simplify.

3a=180°

To isolate a , divide both sides of the equation by 3 .

3a3=180°3    a=60°

The measure of the second angle is,

2a=2×60°       =120°

So, the measures of the two supplementary angles are 60° and 120° .

Step-by-step Example 2:

Find m∠P  and  m∠Q if ∠P  and  ∠Q are supplementary, m∠P=2x+15 , and m∠Q=5x−38 .

The sum of the measures of two supplementary angles is 180° .

So, m∠P+m∠Q=180°

Substitute 2x+15 for m∠P and 5x−38 for m∠Q .

2x+15+5x−38=180°

Combine the like terms. We get:

7x−23=180°

Add 23 to both the sides. We get:

7x=203°

Divide both the sides by 7 .

7x7=203°7

Simplify.

x=29°

To find m∠P , substitute 29 for x in 2x+15 .

2(29)+15=58+15

Simplify.

58+15=73

So, m∠P=73° .

To find m∠Q , substitute 29 for x in 5x−38 .

5(29)−38=145−38

Simplify.

145−38=107

So, m∠Q=107° .

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Andrew [12]

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-5/6, -1/6, 5/3

Step-by-step explanation:

1. the greatest negative number always is the least number.

       When you have questions like this think about it if the numbers were on a numberline.

        -5/6 would go first because that number is the furthest to the left. 5/3 would be the greatest because that number is furthest to the right.

4 0
3 years ago
Slope of the line that passes through (6,0) and (0,-6)
lisov135 [29]

Hey there!

The formula is:

• m = rise / run

• m = y₂ – y₁ / x₂ – x₁

• y₂ = –6

• y₁ = 0

• x₂ = 0

• x₁ = 6

• Equation: “–6 – 0 / 0 – 6”

–6 – 0 = –6 ⬅️ numerator (TOP number)

0 – 6 = –6 ⬅️ denominator (BOTTOM number)

Equation: –6 / –6

SOLVE above and you will have your ANSWER.

–6 / –6 = 1 because double negatives makes a negative.

The slope of line that passes through your given points is: 1

Answer: 1 ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

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Sphinxa [80]

Answer:

Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)

Step-by-step explanation:

Center at (-5,-1) because of the plus 5 added to the x and the plus 1 added to the y.

a(squared)=36 which means a=6 and a=distance from center to vertices so add and subtract 6 from the x coordinate since this is a horizontal hyperbola, which is (1,-1), (-11,-1). From there you dont need to find the focus since there is only one option for this;

Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)

8 0
3 years ago
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