1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Paul [167]
3 years ago
12

PLEASE ANSWER! DESPERATE, DONT KNOW HOW TO DO IT!

Mathematics
1 answer:
Annette [7]3 years ago
5 0

Answer:

a) x = -7

b) x = -3/2

c) x = -3/2

d) x = 2

e) x = -1

f) x = -2

g) x = 7/3

h) z = -18/5

i) x = 6

Explanation:

The are a couple of rules you should know first.

Negative exponent rule: a^{-x} = \frac{1}{a^{x}}

A negative exponent means the same thing as the positive exponent as a denominator under 1.

Exponent to another exponent: (a^{x})^{n}=a^{xn}

When raising an exponent to another exponent, you multiply the exponents.

Fraction as a base rule: (\frac{a}{b})^{x} = \frac{a^{x}}{b^{x}}

Apply the exponent to the numerator and denominator.

Base 1 rule: 1^{x} = 1

1 to the power of anything is 1.

Focus on exponents only: a^{x} = a^{n}\\x = n

If the bases are the same on both sides of the equation, you can solve for "x" in the exponent by focusing on it only.

Write as an exponent: Rewrite a normal number as an exponent instead. Example: 8=2^{3} or 125=5^{3}

Also, you need to know how to rearrange and simplify formulas to isolate variables (by doing reverse operations in reverse BEDMAS order).

Know how to use the distributive property with brackets, when you multiply each of the terms in the brackets with the term on the outside.

Use each of these rules to solve.

a) 2^{x+4} = \frac{1}{8}   Write 8 as exponent

2^{x+4} = \frac{1}{2^{3}}   Negative exponent rule

2^{x+4} = 2^{-3}   Focus on exponents only

x+4 = -3   Subtract 4 from each side to isolate

x = -3-4

x = -7

b) 9^{x}=\frac{1}{27}   Write 27 as exponent

9^{x}=\frac{1}{3^{3}}   Write 9 as exponent

(3^{2})^{x}=\frac{1}{3^{3}}   Exponent to another exponent

3^{2x}=\frac{1}{3^{3}}   Negative exponent rule

3^{2x}=3^{-3}   Focus on exponents only

2x=-3   Divide both sides by 2 to isolate

x=-\frac{3}{2}

c) 25^{x}=\frac{1}{125}   Rewrite 125 as exponent

25^{x}=\frac{1}{5^{3}}   Rewrite 25 as exponent

(5^{2})^{x}=\frac{1}{5^{3}}   Exponent to another exponent

5^{2x}=\frac{1}{5^{3}}   Negative exponent rule

5^{2x}=5^{-3}   Focus only exponents only

2x=-3   Divide both sides by 2 to isolate

x=-\frac{3}{2}

d)  7(3^{x})=63   Divide both sides by 7 to isolate

3^{x}=63/7

3^{x}=9   Write 9 as exponent

3^{x}=3^{2}   Focus on exponents

x=2

e) 10^{3x}=0.001   Write 0.001 as fraction

10^{3x}=\frac{1}{1000}   Write 1/1000 as exponent

10^{3x}=\frac{1}{10^{3}}   Neg. exponent

10^{3x}=10^{-3}   Focus on exponents

3x=-3   Divide both sides by -3

x=-3/3

x=-1

f) 6(\frac{1}{10})^{x}=600   Divide both sides by 6

(\frac{1}{10})^{x}=\frac{600}{6}

(\frac{1}{10})^{x}=100  Write 100 as exponent

(\frac{1}{10})^{x}=10^{2}   Fraction as base rule

\frac{1^{x}}{10^{x}}=10^{2}   Base 1 rule

\frac{1}{10^{x}}=10^{2}   Neg. exponent

10^{-x}=10^{2}   Focus on exponent

-x=2   Divide both sides by -1

x=-2

g) 27^{x-3}=(\frac{1}{3})^{2}   Write 27 as exponent

(3^{3})^{x-3}=(\frac{1}{3})^{2}   Exponent to another exponent

3^{3(x-3)}=(\frac{1}{3})^{2}   Fraction as base

3^{3(x-3)}=\frac{1^{2}}{3^{2}}   Base 1 rule

3^{3(x-3)}=\frac{1}{3^{2}}   Neg. exponent

3^{3(x-3)}=3^{-2}   Focus

3(x-3)=-2   Distribute over brackets

3x-9=-2   Add 9 to both sides

3x=-2+9

3x=7   Div. both sides by 3

x=\frac{7}{3}

h) 4^{\frac{2z}{3}} = 8^{z+2}   Write 4 as exponent

(2^{2})^{\frac{2z}{3}} = 8^{z+2}   Exponent to another exponent

2^{2\frac{2z}{3}} = 8^{z+2}   Write 8 as exponent

2^{2\frac{2z}{3}} = (2^{3})^{z+2}   Exponent to another exponent

2^{2\frac{2z}{3}} = 2^{3(z+2)}   Focus

2\frac{2z}{3} = 3(z+2)   Multiply whole number with fraction

\frac{4z}{3} = 3(z+2)   Distribute

\frac{4z}{3} = 3z+6   Multiply both sides by 3

4z = 3(3z+6)   Distribute

4z = 9z+18   Subtract 9z from both sides

4z-9z = 18

-5z = 18   Div. both sides by -5

z = -\frac{18}{5}

i) 5(2)^{x-1}+3=163   Subtract 3 on both sides

5(2)^{x-1}=163-3

5(2)^{x-1}=160   Div. both sides by 5

(2)^{x-1}=160/5

(2)^{x-1}=32   Write 32 as exponent

(2)^{x-1}=2^{5}   Focus

x-1=5   Add 1 to both sides

x=5+1

x=6

You might be interested in
Use the table to identify the values of p and q that should be used to factor x^2+9x-10 as (x+p)(x+q)
likoan [24]
X^2 + 9x -10 = (x -1)(x +10) = (x +(-1)) (x + 10)
p = -1 and q  = 10
answer is A.
5 0
3 years ago
Read 2 more answers
what is thirty-four million plus two hundred fifty-six thousand times four hundred? Please write the answer in scientific notati
Mashutka [201]
Million has 6 zeoes
34,000,000+256,00*400

PEMDAS
multiply first
256,000*400=102,400,000
add to 34,000,000
136,400,000
now
must be in form
(x)(10^m)
such taht
1<x<10
and x times 10^m is the original number
1.364*10^8
7 0
3 years ago
Read 2 more answers
These tables show equivalent ratios. The value missing in each table is replaced with X. Choose ALL tables in which 12 replaces
marishachu [46]

Answer:

a

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Match the following rational expressions to their rewritten forms.
Nookie1986 [14]

Answer:

Answer image is attached.

Step-by-step explanation:

Given rational expressions:

1.\ \dfrac{x^2+x+4}{x-2}\\2.\ \dfrac{x^2-x+4}{x-2}\\3.\ \dfrac{x^2-4x+10}{x-2}\\4.\ \dfrac{x^2-5x+16}{x-2}

And the rewritten forms:

(x-2)+\dfrac{6}{x-2}\\(x+3)+\dfrac{10}{x-2}\\(x+1)+\dfrac{6}{x-2}\\(x-3)+\dfrac{10}{x-2}

We have to match the rewritten terms with the given expressions.

Let us consider the rewritten terms and let us solve them one by one by taking LCM.

(x-2)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x-2)^{2}+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+4+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+10}{x-2}

So, correct option is 3.

(x+3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x+3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{(x^2+3x-2x-6)+10}{x-2}\\\Rightarrow \dfrac{x^2+x+4}{x-2}

So, correct option is 1.

(x+1)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x+1)(x-2)+6}{x-2}\\\Rightarrow \dfrac{x^{2} +x-2x-2+6}{x-2}\\\Rightarrow \dfrac{x^{2} -x+4}{x-2}

So, correct option is 2.

(x-3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x-3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{x^2-3x-2x+6+10}{x-2}\\\Rightarrow \dfrac{x^2-5x+16}{x-2}

So, correct option is 4.

The answer is also attached in the answer area.

7 0
2 years ago
3. The parents of a newborn girl want to invest $1000 in some kind of saving plan that their child could
andrew11 [14]

Answer:

A. 1000x75t=i

B. 1000(1+5%/n)^t

Step-by-step explanation:

i=prt     interest principle rate time

a=p(1+r/n)^t amount principle rate number of times interest is compound time

<em>Hope this helps.</em>

5 0
2 years ago
Other questions:
  • 17.The diameter of a circle has endpoints P(–7, –10) and Q(3, 2).
    11·1 answer
  • For the rule y= 4 - x2, calculate the y-values that complete the table below
    10·1 answer
  • A marine sales dealer Önds that the average price of a previously owned boat is $6492. He decides to sell boats that will appeal
    6·1 answer
  • What is a.missing term in each proportion 6:n = 8:12
    11·2 answers
  • Jesse uses the function f(x) = 0.25x + 20 to calculate her phone bill each month, in dollars, where x is the number of minutes s
    12·1 answer
  • Sharon is in charge of water bottles for a school field trip.
    5·2 answers
  • Marco surveyed the first 10 people
    7·1 answer
  • What is the slope-intercept equation of the line below? 61 -5
    11·1 answer
  • 5) Establish the indentity (cot + tan ) sin = sec . Show each step to justify your conclusion.
    14·1 answer
  • Little helppp please ​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!