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vagabundo [1.1K]
3 years ago
5

Given the function f(x) = 3x3 + 7x2 + 5x, find f(-3).

Mathematics
1 answer:
Julli [10]3 years ago
4 0

Answer:

the ans is b -33

Step-by-step explanation:

by putting the -3 in the place of x and adding,subtracting

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Gears A and B turn together. Gear A turns 20 times when
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Answer: Gear B turns 90 times when gear A turns 60 times

Step-by-step explanation: To solve this you just 30x3=90

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A car travels at 65 miles per hour. Going through collision,it travels at 3/5 this speed. Write this fraction as a decimal.
solniwko [45]

Answer:

0.6

Step-by-step explanation:

the car moves at a speed of 3/5*65 miles per hour

that is 39 miles per hour

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6 0
3 years ago
In a school, the ratio of musicians to athletes is 3 : 1. The number of musicians is how many times the number of athletes?  ANS
loris [4]

Answer:

The number of musicians in the school is 3 times the number of athletes

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
What are the steps to this equation to -2x-4+5x=8
laila [671]

Answer:

x = 4

Explanation:

−2x − 4 + 5x = 8

[ Simplify both sides of the equation ]

−2x − 4 + 5x = 8

−2x + −4 + 5x = 8

(−2x + 5x) + (−4) = 8 (Combine Like Terms)

3x + −4 = 8

3x − 4 = 8

[ Add 4 to both sides ]

3x − 4 + 4 = 8 + 4

3x = 12

[ Divide both sides by 3 ]

3x / 3 = 12 / 3

x = 4

- PNW

6 0
2 years ago
Read 2 more answers
Find constants a and b such that the function y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 5y = sin(x)
vichka [17]

Answers:

a = -6/37

b = -1/37

============================================================

Explanation:

Let's start things off by computing the derivatives we'll need

y = a\sin(x) + b\cos(x)\\\\y' = a\cos(x) - b\sin(x)\\\\y'' = -a\sin(x) - b\cos(x)\\\\

Apply substitution to get

y'' + y' - 5y = \sin(x)\\\\\left(-a\sin(x) - b\cos(x)\right) + \left(a\cos(x) - b\sin(x)\right) - 5\left(a\sin(x) + b\cos(x)\right) = \sin(x)\\\\-a\sin(x) - b\cos(x) + a\cos(x) - b\sin(x) - 5a\sin(x) - 5b\cos(x) = \sin(x)\\\\\left(-a\sin(x) - b\sin(x) - 5a\sin(x)\right)  + \left(- b\cos(x) + a\cos(x) - 5b\cos(x)\right) = \sin(x)\\\\\left(-a - b - 5a\right)\sin(x)  + \left(- b + a - 5b\right)\cos(x) = \sin(x)\\\\\left(-6a - b\right)\sin(x)  + \left(a - 6b\right)\cos(x) = \sin(x)\\\\

I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.

The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero

a-6b = 0

a = 6b

At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)

-6a  -b = 1

-6(6b) - b = 1 .... plug in a = 6b

-36b - b = 1

-37b = 1

b = -1/37

Use this to find 'a'

a = 6b

a = 6(-1/37)

a = -6/37

8 0
2 years ago
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