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3 years ago

Which of the following is the equation of a line perpendicular to the line, , passing through the point (3,9)?

1 answer:

5 0

Y = -3/2x + 4...slope is -3/2
A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So that means the slope we will need is 2/3...see how I flipped the slope and changed the sign.
Now we use y = mx + b....slope(m) = 2/3....(3,9)...x = 3 and y = 9.
Time to sub...we r looking for b, the y intercept.

9 = 2/3(3) + b
9 = 2 + b
9 - 2 = b
7 = b

so the perpendicular equation is : y = 2/3x + 7...but we need it in Ax + By = C form....
y = 2/3x + 7....multiply by common denominator of 3 to get rid of fractions
3y = 2x + 21...subtract 2x from both sides
-2x + 3y = 21....<== ur answer...normally, I would have multiplied this by -1 to make x positive...but that is not an answer choice

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6 0

3 years ago

Which equations are equivalent to ? 3^3√x+4 =12 Check all that apply.

eimsori [14]

Answer:

option c

x + 4 = 64

and

option e

x = 60

Step-by-step explanation:

Given in the question an expression

3∛x+4 = 12

∛x + 4 = 12/3

∛x + 4 = 4

Take cube on both sides of the equation

∛(x + 4)³ = 4³

x + 4 = 64

x = 64 - 4

x = 60

4 0

2 years ago

Read 2 more answers

I attached the question below :)

jenyasd209 [6]

Answer:

slope = 2, vertical intercept = 10

Step-by-step explanation:

The intercept, also called the y-intercept, is where the line crosses the y-axis

The vertical line (y-int) is crossed at 10, so vertical intercept = 10

Slope equals rise over run:

The line goes up 10 and moves right 5

10/5 = 2

This line has a positive 2 slope

5 0

2 years ago

Find the output, k, when the input, t, is –7. k = 10t -19

kupik [55]

Answer:

k = - 89

Step-by-step explanation:

To calculate the output, substitute t = - 7 into the equation for output, that is

k = 10(- 7) - 19 = - 70 - 19 = - 89

7 0

2 years ago

In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.

vodka [1.7K]

Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

Solution:

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

Finding percent of increase in the newspaper’s circulation from 2000 to 2001:

$\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100$

$\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}$

Finding percent of increase in the newspaper’s circulation from 2001 to 2002:

$\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}$

As we can see 12% < 12.6%

So period of 2001 to 2002 has higher increase percentage.

7 0

2 years ago