Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b

Question

Juliette [100K]

3 years ago

14

Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b

, what is the value of b?
–21
–4
11
27

Mathematics

2 answers:

Ulleksa [173] · Answer 1 · 2022-06-07T10:36:30+03:00

Ulleksa [173]3 years ago

7 0

Answer:

the answer is -21

Step-by-step explanation:

hope i helped

andrey2020 [161] · Answer 2 · 2022-06-07T08:51:42+03:00

andrey2020 [161]3 years ago

3 0

(-4,-5)(-6,3)
slope(m) = (3 - (-5) / (-6 - (-4)
slope(m) = (3 + 5) / (-6 + 4)
slope(m) = 8/-2 = -4

y = mx + b
slope(m) = -4
u can use either of ur points...I will use (-6,3)
3 = -4(-6) + b
3 = 24 + b
3 - 24 = b
- 21 = b <== here ya go