Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b
, what is the value of b?
–21
–4
11
27
2 answers:
Answer:
the answer is -21
Step-by-step explanation:
hope i helped
(-4,-5)(-6,3)
slope(m) = (3 - (-5) / (-6 - (-4)
slope(m) = (3 + 5) / (-6 + 4)
slope(m) = 8/-2 = -4
y = mx + b
slope(m) = -4
u can use either of ur points...I will use (-6,3)
3 = -4(-6) + b
3 = 24 + b
3 - 24 = b
- 21 = b <== here ya go
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