Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
X² = 1/4 ⇒√⇒ x₁ = 1/2, x₂ = -1/2
Answer:
96π or 301.59 in³
Step-by-step explanation:
V(cone) = 1/3πr²h
= 1/3·π·6²·8
= 96π or 301.59
Answer:
The first one
Step-by-step explanation:
answer = 50.2
Is it x times 2 times y times 2? is that what it is asking or is it meaning squared
