All categories

3 years ago

25x^2+40x+16=28Ansa ASAP

1 answer:

8 0

Solution:
1. Move all terms to one side
25{x}^{2}+40x+16-28=0 2. Simplify 25{x}^{2}+40x+16-28 to 25x2+40x−12
25{x}^{2}+40x-12=0 3. Apply the Quadratic Formulax=\frac{-40+20\sqrt{7}}{50},\frac{-40-20\sqrt{7}}{50}

 4. Simplify solutions
x=-\frac{2(2-\sqrt{7})}{5},-\frac{2(2+\sqrt{7})}{5} Done!

You might be interested in

Me ayudan con esa ecuacion por sustitucion con la comprobacion pliss

attashe74 [19]

1/2x+3y/4=5 => (1/2)x + (3/4)y = 5

1/5x+3y/2=2 => (1/5)x + (3/2)y = 2

Eliminate the fractional coefficients: Mult. the first equation by 4 and mult. the second equation by 10:

2x + 15y = 20

Multiply the 1st equation by -1:

-2x - 3y = -20
2x + 15y = 20
-------------------
12y = 0, so y = 0. Then the first equation becomes 2x + 3(0) = 20, or
x=10.

Solution is (10,0).

8 0

3 years ago

BRAINLIESTT ASAP! PLEASE HELP ME :) Solve for x in the figure below. Show your work.

nikdorinn [45]

Answer:

x = 19°

Step-by-step explanation:

we can see from observation that 22° and (3x+11)° are complementary. I.e they add up to 90°

hence

22 + (3x+11) = 90

22 + 3x+11 = 90

33 + 3x = 90 (divide both sides by 3)

11 + x = 30 (subtract 11 from both sides)

x = 30 - 11

x = 19°

7 0

3 years ago

Read 2 more answers

George ate 4 slices of pizza if this was 25% of the slices at the dinner table how many slices were there at the table to start

Lisa [10]

There were 16 slices

5 0

3 years ago

Help please in both questions ): ?

Elina [12.6K]

Answer:

The angle corresponding to angle 4 is angle 8

4 0

2 years ago

Read 2 more answers

I need to use the Pythagorean Theorem to find X. I don’t know how to do that!!

frutty [35]

Answer:

17) x=8

18) $x=\sqrt{189}$ or $x= 3\sqrt{21}$

Step-by-step explanation:

So the rule is $a^{2} +b^{2} =c^{2}$ , "c" being the hypothenuse, or the long line that is opposite to the right angle.

17) We know that both values of x are equal to each other, which makes everything 10x easier!

$x^{2} +x^{2} =(8\sqrt{2}) ^{2}$

(by the way we know the x values are our a and b values because they are legs! the way I like to remember the legs is that they are connected to the right angle box, and therefore support the hypothenuse)

simplify (╥︣﹏╥)

$2x^2=8^2(\sqrt{2} )^{2}$

$2x^2=64(2)$

$2x^2=128$

$x^{2}= 128/2$

$x^{2} =64$

x=8

18) Just pretend that the flipped triangle doesn't exist. It's parallel to the other triangle with values on it, and basically servers no purpose other than being parallel to the sister triangle :)

Anyways, since we know the hypothenuse (15) but we don't know one of our leg values (x), we're going to change our equation a bit!

$c^{2} - b^{2} = a^{2}$