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3 years ago

6

25x^2+40x+16=28Ansa ASAP

1 answer:

Paha777 [63]3 years ago

8 0

Solution:
1. Move all terms to one side
<span>25{x}^{2}+40x+16-28=0</span> 2. Simplify <span>25{x}^{2}+40x+16-28 to <span>25<span>x<span><span>2</span><span></span></span></span>+40x</span></span><span><span>−12</span></span>
<span>25{x}^{2}+40x-12=0</span> 3. Apply the Quadratic Formula<span>x=\frac{-40+20\sqrt{7}}{50},\frac{-40-20\sqrt{7}}{50}

</span> 4. Simplify solutions
<span>x=-\frac{2(2-\sqrt{7})}{5},-\frac{2(2+\sqrt{7})}{5}</span> Done!

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