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ira [324]
3 years ago
13

What tool enables you to easily delete, add, or resize filesystems without regard to their physical locations on a hard disk?

Computers and Technology
1 answer:
frosja888 [35]3 years ago
7 0

Answer:

Logical Volume Management Tool

Explanation:

With Logical Volume Management(LVM), administrators and even users are offered a more flexible approach of managing space in disk storage. LVM provides method for sharing space(volume) on large storage devices (such as hard disk) with such greater flexibility than conventional partitioning strategies to store data. With LVM, users can easily duplicate, delete, add, resize and even file systems without much information about their physical locations on the storage device.

<em>Hope this helps!</em>

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Que se trata el RUC<br>​
mariarad [96]
No se senor i no sure
7 0
3 years ago
The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices
erma4kov [3.2K]

Answer:

In Java:

import java.util.Scanner;  

import java.util.Arrays;  

public class Main  {  

public static void main(String args[])  {  

Scanner input = new Scanner(System.in);

int row, col;  

System.out.print("Rows: ");    row = input.nextInt();

System.out.print("Cols: ");     col = input.nextInt();  

int[][] Array2D = new int[row][col];

System.out.print("Enter array elements: ");

for(int i =0;i<row;i++){    

    for(int j =0;j<col;j++){

        Array2D[i][j] = input.nextInt();  

    }     }

 

int[] maxarray = findmax(Array2D,row,col);

System.out.println("Row: "+(maxarray[0]+1));

System.out.println("Column: "+(maxarray[1]+1));

}  

public static int[] findmax(int[][] Array2D,int row, int col)   {  

int max = Array2D[0][0];

int []maxitem = new int [2];

for(int i =0;i<row;i++){

    for(int j =0;j<col;j++){

        if(Array2D[i][j] > max){  

            maxitem[0] = i;

            maxitem[1] = j; } }    }

 

return maxitem;  

}  

}

Explanation:

The next two lines import the scanner and array libraries

<em>import java.util.Scanner;   </em>

<em>import java.util.Arrays;   </em>

The class of the program

<em>public class Main  {  </em>

The main method begins here

<em>public static void main(String args[])  {  </em>

The scanner function is called in the program

<em>Scanner input = new Scanner(System.in);</em>

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input  

System.out.print("Rows: ");    row = input.nextInt();

This next instructions prompt the user for columns and get the column input  

System.out.print("Cols: ");     col = input.nextInt();  

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

<em> for(int i =0;i<row;i++){    </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         Array2D[i][j] = input.nextInt();   </em>

<em>     }     } </em>

This calls the findmax function. The returned array of the function is saved in maxarray  

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}  

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col)   {  

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

<em>for(int i =0;i<row;i++){ </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         if(Array2D[i][j] > max){  </em>

<em>             maxitem[0] = i; </em><em>-- The row position is saved in index 0</em><em> </em>

<em>             maxitem[1] = j;  </em><em>-- The column position is saved in index 1</em><em>} }    } </em>

This returns the 1 d array

return maxitem;  

}  

7 0
3 years ago
When a device or service causes the system to hang during a normal boot, boot into __________ and disable the device or service
Olenka [21]

You should boot into <u>safe mode</u> and disable the device or service when it causes the computer system to hang during a normal boot.

<h3>What is safe mood?</h3>

Safe mood can be defined as a boot option in which the operating system (OS) of a computer system starts in <u>diagnostic mode</u> rather than in a normal operating mode, so as to enable the user correct any problems preventing the computer system to have a normal boot.

This ultimately implies that, safe mood is a diagnostic mode of the operating system (OS) of a computer system that is designed and developed to fix most problems within an operating system (OS) and for the removal of rogue software applications.

Read more on safe mood here: brainly.com/question/13026618

5 0
2 years ago
Write a method starString that accepts an integer parameter n and returns a string of stars (asterisks) 2n long (i.e., 2 to the
lys-0071 [83]

Answer:

public class Main

{

public static void main(String[] args) {

 System.out.println(starString(4));

}

public static String starString(int n){

    double p = Math.pow(2,n);

    String s = "";

    for(int i=0; i<p; i++)

        s += "*";

       

   return s;

}

}

Explanation:

Create a method named starString that takes an integer parameter, n

Get the 2 to the nth power using pow method and set it to the p

Create an empty string that will hold the asterisks

Create a for loop that will iterate p times. Inside the loop, concatenate an asterisk to the s

Return the s

Inside the main method, call the method with an integer parameter

4 0
3 years ago
first 2 questions are true or false the last question is multiple choice. 7th grade work. plz only answer if u know.
pshichka [43]

#4 is true

We use pseudocode to help us understand code.

#5 is false

Strings are surrounded by quotes, integers are not.

#6 is 100.

Integers are numbers with no decimal places.

3 0
3 years ago
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