I think the answer is scanning.
Answer:
def printRange(start, stop, steps = 1):
list1 = []
if steps > start or stop:
print("Steps is larger than start and stop value")
return None
if int(start) < int(stop):
while start < stop:
start = start + int(steps)
list1.append(start)
print(list1)
elif start > stop:
while start > stop:
stop = stop + int(steps)
list1.append(stop)
print(list1)
elif start == stop:
print(start)
else:
print("Values are not integers.")
for easier viewing:
https://www.codepile.net/pile/e95verLk
If you need help understanding comment below.
Answer:
When designing a cache, you have to consider this things:
If the cache has a bigger block size may have a lower delay, but when miss the miss rate will be costly. If an application has high spatial locality a bigger block size will do well, but programs with poor spatial locality will not because a miss rate will be high and seek time will be expensive.
Answer:
Check explanation
Explanation:
Two stacks can make use of one array by utilizing various stack pointers that begins from different ends of an array. Looking at the array A[1...
], the first stack will drive elements that starts from position 1 as well as to move its' pointer to .
The Second stack will begin at the position and motion its' pointer to 1. The best likely divide is to offer each stack a half of an array. whenever any of two stacks transverse the half-point, an overflow can happen but for that overall number of elements, it must be
