Answer:
Examples of input devices include keyboards, mouse, scanners, digital cameras, joysticks, and microphones.
Explanation:An input device is a piece of computer hardware equipment used to provide data and control signals to an information processing system such as a computer or information appliance.
There are many ways it cna illustrate kindness, such as making friends
with friendly people, keeping long distance relationships possible,
raising awareness of an event
<em>A</em><em> </em><em> </em><em>WAn</em><em> </em><em>(</em><em> </em><em>Wide</em><em> </em><em>Area</em><em> </em><em>Network</em><em> </em><em>)</em><em> </em><em>is</em><em> </em><em>made</em><em> </em><em>up</em><em> </em><em>of</em><em> </em><em>LANS</em><em> </em><em>(</em><em> </em><em>Local</em><em> </em><em>Area</em><em> </em><em>Network</em><em>)</em><em>…</em><em>…</em><em>…</em><em>…</em>
Answer: Option (c) is correct
Explanation:
PDF is portable document format that come in form of file format .It is used for sharing and transmitting between computing and operating systems for viewing and printing in actual page layout. They can be used fro eBooks ,scanned document and text etc.
- Other options are incorrect because not all business organization use PDF, PDF has the capability of being edited and it stands for "portable document format".
- Thus, the correct option is option(c)
Alternative 1:A small D-cache with a hit rate of 94% and a hit access time of 1 cycle (assume that no additional cycles on top of the baseline CPI are added to the execution on a cache hit in this case).Alternative 2: A larger D-cache with a hit rate of 98% and the hit access time of 2 cycles (assume that every memory instruction that hits into the cache adds one additional cycle on top of the baseline CPI). a)[10%] Estimate the CPI metric for both of these designs and determine which of these two designsprovides better performance. Explain your answers!CPI = # Cycles / # InsnLet X = # InsnCPI = # Cycles / XAlternative 1:# Cycles = 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150)CPI= 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150) / X1= X(0.50*2 + 0.50(0.94*2 + 0.06*150) ) / X= 0.50*2 + 0.50(0.94*2 + 0.06*150)= 6.44Alternative 2:# Cycles = 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150)CPI= 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150) / X2= X(0.50*2 + 0.50(0.98*(2+1) + 0.02*150)) / X= 0.50*2 + 0.50(0.98*(2+1) + 0.02*150)= 3.97Alternative 2 has a lower CPI, therefore Alternative 2 provides better performance.
