Answer:
the second last option
Explanation:
secure HTTP is armed with passwords to ensure that only authorised users gain entry.
the data is encrypted during transmission
Answer:
an aptitude test.
Explanation:
Based on the scenario being described it can be said that the test that Francis is scheduled to take would be classified as an aptitude test. This is a test that tries to determine an individual's innate ability at a particular competency. These are abilities such as sequencing skills and abstract reasoning skills, and are the results of these tests are used in order to see where a candidate can best be placed within a program/company to best perform.
Answer:
False
Explanation:
The answer to this question is false. This is because the NVD doesn't perform such tests on their own. Instead they they rely on third-party vendors, software researchers, etc to get such reports and do the assignment of CVSS scores for softwares
The National Vulnerability Database (NVD) is the United State governments leading resource for software vulnerability
Answer: E-mails
Explanation:
An E-mails is one of the type of digital message and also known as the dominant communication tool which is used for in the form of document in an organization where we can used it in different ways are as follows:
- Communicating with other employees related to rules and regulations of an organization
- Making various types of recommendations
- Used for an inquiry purpose
- providing various types of current status and new updates
According to the given question, Emails is one of the type of tool that is used as the communication medium and it is one of the flexible message delivery options which is widely used by an organizations.
Answer:
boolean isEven = false;
if (x.length % 2 == 0)
isEven = true;
Comparable currentMax;
int currentMaxIndex;
for (int i = x.length - 1; i >= 1; i--)
{
currentMax = x[i];
currentMaxIndex = i;
for (int j = i - 1; j >= 0; j--)
{
if (((Comparable)currentMax).compareTo(x[j]) < 0)
{
currentMax = x[j];
currentMaxIndex = j;
}
}
x[currentMaxIndex] = x[i];
x[i] = currentMax;
}
Comparable a = null;
Comparable b = null;
if (isEven == true)
{
a = x[x.length/2];
b = x[(x.length/2) - 1];
if ((a).compareTo(b) > 0)
m = a;
else
m = b;
}
else
m = x[x.length/2];
