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elixir [45]
2 years ago
5

Write a lottery program that will ask the user if they would like to pick 5 numbers (1-30) or if they would like to choose EZ Pi

ck where the computer randomly picks their 5 numbers at a cost of $1.00. Then you will give them a chance to also play the Next Chance drawing for an extra $1.00. They do not choose additional numbers for the Next Chance drawing. Once they have all of their selections complete, have the computer game generate the five random winning numbers and if they opted for the Next Chance drawing, select 4 more random numbers. Display all of the users numbers, all of the winning numbers, and display how much, if any, that the player has won based on the following information:
Computers and Technology
1 answer:
Llana [10]2 years ago
6 0

Answer:

Explanation:

The following code is written in Python and creates arrays for the user's numbers and the next chance numbers, it also creates a cost variable and a did_you_win variable. The function takes in the winning numbers as an array parameter. It asks all the necessary questions to generate data for all the variables and then compares the user's numbers to the winning numbers in order to detect if the user has won. Finally, it prints all the necessary information.

import random

def lottery(winning_numbers):

   user_numbers = []

   next_chance_drawing = []

   cost = 0

   did_you_win = "No"

   #print("Would you like to choose your own 5 numbers? Y or N")

   answer = input("Would you like to choose your own 5 numbers? Y or N: ")

   if answer.capitalize() == "Y":

       for x in range(5):

           user_numbers.append(input("Enter number " + str(x+1) + ": "))

   else:

       for x in range(5):

           user_numbers.append(random.randint(0,31))

           cost += 1

   next_chance = input("Would you like to enter a Next Chance drawing for $1.00? Y or N: ")

   if next_chance.capitalize() == "Y":

       for x in range(4):

           next_chance_drawing.append(random.randint(0, 31))

           cost += 1

           

   if user_numbers == winning_numbers or next_chance_drawing == winning_numbers:

       did_you_win = "Yes"

   print("User Numbers: " + str(user_numbers))

   print("Next Chance Numbers: " + str(next_chance_drawing))

   print("Cost: $" + str(cost))

   print("Did you win: " + did_you_win)

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5 0
3 years ago
Create a macro named mReadInt that reads a 16- or 32-bit signed integer from standard input and returns the value in an argument
timofeeve [1]

Answer:

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

Explanation:

For an assembly code/language that has the conditions given in the question, the program that tests the macro, passing it operands of various sizes is given below;

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

7 0
3 years ago
Write a copy assignment operator for CarCounter that assigns objToCopy.carCount to the new objects's carCount, then returns *thi
Olin [163]

The following cose will be used to copy assignment operator for CarCounter

<u>Explanation:</u>

Complete Program:

#include <iostream>

using namespace std;

class CarCounter

{

public:

CarCounter();

CarCounter& operator=(const CarCounter& objToCopy);

void SetCarCount(const int setVal)

{

 carCount = setVal;

}

int GetCarCount() const

{

 return carCount;

}

private:

int carCount;

};

CarCounter::CarCounter()

{

carCount = 0;

return;

}

// FIXME write copy assignment operator

/* Your solution goes here */

CarCounter& CarCounter::operator=(const CarCounter& objToCopy)

{

if(this != &objToCopy)

 carCount = objToCopy.carCount;

return *this;

}

int main()

{

CarCounter frontParkingLot;

CarCounter backParkingLot;

frontParkingLot.SetCarCount(12);

backParkingLot = frontParkingLot;

cout << "Cars counted: " << backParkingLot.GetCarCount();

cout << endl << endl;

system("pause");

return 0;

}

5 0
3 years ago
Please help!! thank you so much!! &lt;3
Zepler [3.9K]

Answer:

D. 4x as much

Explanation:

The answer is pretty simple. The question is asking about 10m/s and 20m/s right? Take a look at the energy at each point on the graph. At 10m/s the kinetic energy is 100 on the graph. At 20m/s the kinetic energy is 400. You'll notice that 100 x 4 is 400 - That's the answer.

You can also prove this mathematically. The formula for kinetic energy is

\frac{1}{2}mv^2

The question says: constant mass so we can ignore that for now.

(1/2) * 10^2 is (1/2) * 100 = 50

for the 20m/s ball it would be

(1/2) * 20^2 = 400 * 1/2 = 200

Once again, you see that it is 4x

3 0
3 years ago
Read 2 more answers
Write a program that reads whitespace delimited strings (words) and an integer (freq). Then, the program outputs the strings fro
Lesechka [4]

Answer:

See explaination for the code

Explanation:

def wordsOfFrequency(words, freq):

d = {}

res = []

for i in range(len(words)):

if(words[i].lower() in d):

d[words[i].lower()] = d[words[i].lower()] + 1

else:

d[words[i].lower()] = 1

for word in words:

if d[word.lower()]==freq:

res.append(word)

return res

Note:

First a dictionary is created to keep the count of the lowercase form of each word.

Then, using another for loop, each word count is matched with the freq, if it matches, the word is appended to the result list res.

Finally the res list is appended.

3 0
3 years ago
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