Use the phase diagram above to answer the questions below .( Remember that standard pressure is 1.00 atm and it’s used to find n
ormal phase change temperatures.)
1: In which state/phase of matter is this substance at -10 °C and a pressure of 0.50 atm?
2: What phase change occurs as the substance at 0.75 atm is heated from 0°C to 25°C
3: The normal boiling point of a substance is the temperature at standard pressure (1 atm) in which a substance changes from the liquid to the gas/vapor state . What is the normal boiling point of this substance ?
4: The point on the phase diagram where the separation line between liquid and gas ends and the distinction between the liquid phase and gas phase disappears is called the ___________ . At this point ,no amount of pressure will cause the substance to condense into a liquid
5: What is the temperature and pressure of the triple point?
What phases are in equilibrium at this point ?
6: What phase change occurs as the substance at 0°C has its pressure dropped from 0.50 atm to 0.25 atm?
1: In which state/phase of matter is this substance at -10 °C and a pressure of 0.50 atm?
2: What phase change occurs as the substance at 0.75 atm is heated from 0°C to 25°C
3: The normal boiling point of a substance is the temperature at standard pressure (1 atm) in which a substance changes from the liquid to the gas/vapor state . What is the normal boiling point of this substance ?
4: The point on the phase diagram where the separation line between liquid and gas ends and the distinction between the liquid phase and gas phase disappears is called the ___________ . At this point ,no amount of pressure will cause the substance to condense into a liquid
5: What is the temperature and pressure of the triple point?
What phases are in equilibrium at this point ?
6: What phase change occurs as the substance at 0°C has its pressure dropped from 0.50 atm to 0.25 atm?
2 answers:
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Answer:
Ek1 = 900000 [J]
Ek1 = 400000 [J]
Explanation:
In order to solve this problem we must remember that kinetic energy is defined as the product of mass by velocity squared by a medium. Therefore using the following equation we have:
where:
m = mass = 500 [kg]
v1 = 60 [m/s]
So we have:
Ek1 = 0.5*500*(60^2)
Ek1 = 900000 [J]
and:
Ek2 = 0.5*500*(40^2)
Ek2 = 400000 [J]
Answer
given,
mass of ball = 5.93 kg
length of the string = 2.35 m
revolve with velocity of 4.75 m/s
acceleration due to gravity = 9.81 m/s²
T cos θ = mg
T cos θ =
T cos θ = 58.17
T² - 56.93T - 3383.75 = 0
T = 93.22 N
θ = 51.39°