Use the phase diagram above to answer the questions below .( Remember that standard pressure is 1.00 atm and it’s used to find n
ormal phase change temperatures.)
1: In which state/phase of matter is this substance at -10 °C and a pressure of 0.50 atm?
2: What phase change occurs as the substance at 0.75 atm is heated from 0°C to 25°C
3: The normal boiling point of a substance is the temperature at standard pressure (1 atm) in which a substance changes from the liquid to the gas/vapor state . What is the normal boiling point of this substance ?
4: The point on the phase diagram where the separation line between liquid and gas ends and the distinction between the liquid phase and gas phase disappears is called the ___________ . At this point ,no amount of pressure will cause the substance to condense into a liquid
5: What is the temperature and pressure of the triple point?
What phases are in equilibrium at this point ?
6: What phase change occurs as the substance at 0°C has its pressure dropped from 0.50 atm to 0.25 atm?
1: In which state/phase of matter is this substance at -10 °C and a pressure of 0.50 atm?
2: What phase change occurs as the substance at 0.75 atm is heated from 0°C to 25°C
3: The normal boiling point of a substance is the temperature at standard pressure (1 atm) in which a substance changes from the liquid to the gas/vapor state . What is the normal boiling point of this substance ?
4: The point on the phase diagram where the separation line between liquid and gas ends and the distinction between the liquid phase and gas phase disappears is called the ___________ . At this point ,no amount of pressure will cause the substance to condense into a liquid
5: What is the temperature and pressure of the triple point?
What phases are in equilibrium at this point ?
6: What phase change occurs as the substance at 0°C has its pressure dropped from 0.50 atm to 0.25 atm?
2 answers:
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Given parameters:
Speed of car = 50m/s
Time of travel = 5minutes (300s)
Unknown;
Distance of travel = ?
To solve this problem, we need to understand how speed relates with distance and time.
Speed is a physical quantity. It is the distance traveled divided by time taken.
Speed =
So,
Distance = speed x time
Input the parameters and solve for the distance;
Distance = 50m/s x 300s
Distance = 15000m
The distance covered during this time interval and speed is 15000m