Answer: The force constant k is 10600 kg/s^2
Step by step:
Use the law of energy conservation. When the elevator hits the spring, it has a certain kinetic and a potential energy. When the elevator reaches the point of still stand the kinetic and potential energies have been transformed to work performed by the elevator in the form of friction (brake clamp) and loading the spring.
Let us define the vertical height axis as having two points: h=2m at the point of elevator hitting the spring, and h=0m at the point of stopping.
The total energy at the point h=2m is:

The total energy at the point h=0m is:

The two Energy values are to be equal (by law of energy conservation), which allows us to determine the only unknown, namely the force constant k:

Answer:
Explanation:
according to third equation of motion
2as=vf²-vi²
vf²=2as+vi²
vf=√2as+vi²
vf=√2as+vi
vf=√2*2*4+3
vf=√16+3
vf=4+3=7
so final velocity is 7 m/s
Answer:
The impuise is 7.9905 kg*m/s
Explanation:
Step one:
given data
v1= +2.63m/s
v2=-20.2m/s
mass m= 0.350kg
Step two:
From the expression for impulse
Ft= mΔv
substituting our data into the expression we have
Ft= 0.35*(-20.2-2.63)
Ft= 0.35*22.83
Ft=7.9905 kg*m/s
Answer:
E = 1/2 M V^2 = 1/2 P V since P = M V
E2 / E1 = P2 V2 / (P1 V1)
P2 / P1 = E2 V1 / (E1 V2) = V2^2 V1 / (V1^2 V2) = V2 / V1
E2 / E1 = V2^2 / V1^2
V2 / V1 = (E2 / E1)^1/2
V2 / V1 = (.9)1/2 = .95
The linear momentum would have to decrease by 5%