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3 years ago

Both X-rays and gamma rays have higher frequencies than ultraviolet rays True or False

Physics

2 answers:

Masja [62]3 years ago

8 0

I’m pretty sure the answer is true

mamaluj [8]3 years ago

7 0

Answer:

i believe its True

Explanation:

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How do elastic objects behave when different forces are applied?

eimsori [14]

They both move in the opposite direction in which they hit

8 0

3 years ago

helpppp I just saw my crush when I was walking out of a supermarket and like I was looking a mess so now I'm just wondering how

UkoKoshka [18]

Answer:

okay

Explanation:

(wish i could help but im just answering for points)

3 0

3 years ago

Kundan who weighs 200N and bijaya who weighs 500N are playing sea saw.If Bijaya is 1m away from the fulcrum,how far should kunda

Tom [10]

Answer:

Kundan should sit at more that 2.5 meters from the location of the fulcrum on the side opposite to the side where Bijaya sits

Explanation:

The given parameters are;

The weight of Kundan, F₁ = 200 N

The weight of Bijaya, F₂ = 500 N

The distance of Bijaya from the fulcrum, d₂ = 1 m

Therefore, for Kundan to lift Bijaya, Kundan should sit at a location further than the point where both the moment of Bijaya and Kundan about the fulcrum are equal

Moment of a force, M = The magnitude of the force, F × The perpendicular distance to the point at which the force acts, d

At equilibrium, the sum of the clockwise moment = The sum of the anticlockwise moment

Taking the moment of Kundan as being in the anticlockwise direction and the moment of Bijaya as acting in the clockwise direction, we have;

F₁ × d₁ = F₂ × d₂

∴ 200 N × d₁ = 500 N × 1 m

d₁ = 500 N·m/(200 N) = 2.5 m

Therefore, when Kundan sits at the point d₁ = 2.5 m, away from the fulcrum on one side of the sea saw and Bijaya sits at the point 1 m from the fulcrum on the other side of the sea saw, both Kundan and Bijaya will have the same moment

For Kundan to lift Bijaya, therefore, Kundan as to sit at a point further than 2.5 m from the fulcrum on the opposite side of the fulcrum from Bijaya.

8 0

3 years ago

If a power utility were able to replace an existing 500 kV transmission line with one operating at 1 MV, it would change the amo

mestny [16]

Answer:

It would change the amount of heat produced in the transmission line to four times the previous value.

Explanation:

Given;

initial voltage in the transmission line, V₁ = 500 kV = 500,000 V

Final voltage in the transmission line, V₂ = 1 MV = 1,000,000

The power lost in the transmission line due to heat is given by;

$P = \frac{V^2}{R}$