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vovikov84 [41]
3 years ago
14

If the cyclist has 2000 j of potential energy at point c how high is the hill

Physics
1 answer:
fgiga [73]3 years ago
5 0

That's really going to depend on ...

-- where point-c is

and

-- the cyclist's mass

and

-- the acceleration of gravity on the planet where the hill is

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If a wave has amplitude of 0.2 meters, a wavelength of 0.5 meters, and a frequency of 32 Hz, at what speed is it moving?
GarryVolchara [31]
The velocity, frequency and wavelength of a wave are related by:
v = fλ
v = 32 x 0.5
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3 years ago
a 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. what is its kinetic energy when it's 2.00 m above the ground
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Answer:

KE_2 = 3.48J

Explanation:

Conservation of Energy

E_1 = E_2

PE_1+KE_1 = PE_2+KE_2

m*g*h+(1/2)m*v² = m*g*h+(1/2)m*v²

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4.10J+0.914J = 1.53J + KE_2

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3 0
3 years ago
Can someone help with these
dedylja [7]

6.  0N.  This questions requires understanding of how friction functions.  Friction is a resistive force, meaning it opposes the direction of any applied or unbalanced forces.  The box in the question experiences no horizontal force, so there is no resistive force in response to it, making it 0N.


7.  This question tests your understanding of static friction.  Static friction only applies when an applied or unbalanced force is applied to an object which does not move.  The static friction always equals the magnitude of the applied or unbalanced force component parallel to the surface which the object rests on.  The question states that the crate starts to move only when the applied force exceeds 313N, so we use this value to determine the force of static friction.  The additional info in the question pertaining to when the crate is moving is irrelevant when determining static friction (only relevant if determining kinetic friction).  Knowing this we solve for the weight of the crate:

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The weight of the crate is also equal to the Normal Force since the object rests on a horizontal surface and the applied force is horizontal as well.  In this question, since the object is not moving at 313N of applied force, the magnitude of static friction equals the applied force:

Ff = μs * Fn

(313) = μs (441)

0.71 (rounded) = μs


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3 years ago
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