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Fed [463]
3 years ago
14

Factor completely 2x^3-6x^2+5x-15

Mathematics
1 answer:
Olenka [21]3 years ago
4 0
2x^3-6x^2+5x-15 

2x^2(x-3)+5(x-3) 

(x-3)(2x^2+5)
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robert buys a car for $8000. at the end of each year the value of the car has decreased by 10% of its value at the beginning of
kiruha [24]
So I believe you will have to do 10% x 7 as it has been seven years which will be 70% and 70% of 8000 is 5600 so the answer will be £5600
3 0
3 years ago
The first four terms of an arithmetic sequence are given by a1= 6, a2 = 12,
Advocard [28]

Answer:

an=6+6(n-1)

Step-by-step explanation:

6 0
3 years ago
Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet
zmey [24]

Answer:

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

hypotenuse^2=perpendicular^2+base^2

hypotenuse^2=(5)^2+(12)^2

hypotenuse^2=25+144

hypotenuse^2=169

Taking square root on both sides.

hypotenuse=13

In a right angled triangle

\sin \theta = \dfrac{opposite}{hypotenuse}

\sin \theta = \dfrac{5}{13}

\sec \theta = \dfrac{hypotenuse}{adjacent}

\sec \theta = \dfrac{13}{12}

In second quadrant only sine and cosecant are positive.

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

6 0
3 years ago
How would you write the function shown in the function machine in function notation
kow [346]
Wow. this is too difficult for me
7 0
2 years ago
Is it possible for a line to pass through only one quadrant?<br> How about four quadrants? explain
neonofarm [45]
Yes it is possible for a line to only start in one quadrant and never leave that quadrant and vice versa a line can start in one quadrant and pass into another quadrant but how will you know if you line will be in certain or multiple quadrants simple just look at your points given if you have the points (3,4) (4,5) you notice that your X's are positive and your Y's are positive there is only one quadrant were your X and Y are positive and that is quadrant 1 but lets say you have points (-4,5),(3,4) you see how one of the points have a negative X and a positive Y there is only one quadrant that has a negative X and a positive Y that is quadrant 2 and and for point (3,4) that is in quadrant 1 so your line will run through quadrant 2 and 1 

yes it is possible for a line to only be in one quadrant and it is also possible for a line to be in multiple quadrants basically it can be any place on a plane  
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8 0
3 years ago
Read 2 more answers
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