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evablogger [386]
4 years ago
6

Lol I hate these problems that's why I keep asking them.... thank you by the way.

Mathematics
1 answer:
Murljashka [212]4 years ago
8 0
Subtract 9 so you have -2. Kx=-2 divide both sides by k. You have -2 over k
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What is the value of 2 in 0.259
expeople1 [14]
The two is in the tenths place. 
4 0
4 years ago
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The description below represents Function A and the table represents Function B:
ICE Princess25 [194]
The expression in A is equal to: 
                      y = 8 + 3x
It can be observed that the equation is in the slope-intercept form which is equal to,
                     y = mx + b
where m is slope and b is intercept.

The slope and intercept therefore of this equation of the line are equal to 3 and 8, respectively.

For Part B:
 The slope of the line can be calculated through the equation,
                           m = (y₂ - y₁) / (x₂ - x₁)
Substituting,
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The intercept, b, is the value of y when x = 0. From the tabulation, y = 5 when x = 0. Thus, the intercept is equal to 5.

Comparing the slopes and intercepts of the equations, we can say that the slope of the second is only half that of the first and the intercept of the second is 3 less than that of the first equation. 
6 0
3 years ago
a submarine ascended 3/8 mile and the descended .4 of a mile followed by another 2/5 mile descent, finally it rose .75 of a mile
shusha [124]

Do you still need the answer? lol.

5 0
4 years ago
for a fixed voltage, the current in an electrical circuit varies inversely as the resistance in the circuit. If a certain has a
Tatiana [17]

Answer:  1.75 amps

<u>Step-by-step explanation:</u>

V (voltage) = I (current) · R (resistance)

              V =    3.5 (110)

                 =   385

When Resistance is doubled, the current is cut in half.

             V = I R

         385 = I (2 · 110)

         \dfrac{385}{220}=\text{I}

         1.75 = I          

7 0
3 years ago
How do I solve k - 16/5 = k + 4
KengaRu [80]
You can't, the K cancels itself out. There is no solution to this
6 0
3 years ago
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