Since 3 < pi < 4,
<span>√9 < pi √16 </span>
<span>In fact, since pi^2 = 9.86, </span>
<span>√9 < pi < √10
</span>
Answer:
<h2> The are of the office is 15ft^2</h2>
Step-by-step explanation:
This problem is on the mensuration of flat shapes, this time on the square shape of an office.
given that
length of the office= 5 feet
width of the office= 3 feet
we can continue y solving for the area of the office, seeing that the information given by the question is just enough for the area
area of square= lenght* width
area= 5*3
area= 15 ft^2
The are of the office is 15ft^2
One $10 bill, Two $1 bills, Two Quarters, Two Nickels
Two $5 bills, Two $1 bills, Two Quarters, Two Nickles
One $10 bill, One $1 bill, Six Quarters, Two Nickles
The diagonal of a rectangle = sqrt(w^2 + l^2)
w = width
l = length
In this problem,
The diagonal = 20 in
w = x
l = 2x + 8
Let's plug our numbers into the formula above.
20in = sqrt((x)^2 + (2x + 8)^2)
Let's simplify the inside of the sqrt
20 in = sqrt(5x^2 + 32x + 64)
Now, let's square both sides.
400 = 5x^2 + 32x + 64
Subtract 400 from both sides.
0 = 5x^2 + 32x - 336
Factor
0 = (5x - 28)(x + 12)
Set both terms equal to zero and solve.
x + 12 = 0
Subtract 12 from both sides.
x = -12
5x - 28 = 0
Add 28 to both sides.
5x = 28
Divide both sides by 5
x = 28/5
The width cant be a negative number so now we know that the only real solution is 28/5
Let's plug 28/5 into our length equation.
Length = 2(28/5) + 8 = 56/5 + 8 = 96/5
In conclusion,
Length = 96/5 inches
Width = 28/5
