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dmitriy555 [2]
3 years ago
6

Using the answers from z^4=16 determine the solutions of the equation (x+1)^4=16(x-1)^4​

Mathematics
1 answer:
Artemon [7]3 years ago
4 0

i hope i have been useful buddy.

good luck ♥️♥️♥️♥️♥️.

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Between which two square roots of integers would you find pi?
Aneli [31]
Since 3 < pi < 4, 
<span>√9 < pi √16 </span>

<span>In fact, since pi^2 = 9.86, </span>

<span>√9 < pi < √10
</span>
6 0
3 years ago
Monica’s current office is a square. Her office in the company’s new building will be 3 feet wider and 5 feet longer
gregori [183]

Answer:

<h2> The are of the office is 15ft^2</h2>

Step-by-step explanation:

This problem is on the mensuration of flat shapes, this time on the square shape of an office.

given that

length of the office= 5 feet

width of the office= 3 feet

we can continue y solving for the area of the office, seeing that the information given by the question is just enough for the area

area of square= lenght* width

area= 5*3

area= 15 ft^2

The are of the office is 15ft^2

7 0
3 years ago
Felicia wants to buy a new soccer ball. it is on sale for $12.60 She has one $10 bill,two $5 bills,three$1 bills,6 quarters,and
gladu [14]
One $10 bill, Two $1 bills, Two Quarters, Two Nickels

Two $5 bills, Two $1 bills, Two Quarters, Two Nickles

One $10 bill, One $1 bill, Six Quarters, Two Nickles


5 0
3 years ago
Compare the functions below:
rjkz [21]
f(x)\to y_{max}=4\\\\g(x)=4\cos(2x-\pi)-2\to y_{max}=2\\\\h(x)=-(x-5)^2+3\to y_{max}=3

Answer: a. f(x)
6 0
3 years ago
Read 2 more answers
An arhitect wants to draw a rectangle with a diagonal of 20 inches. The length of the rectangle is to be 8 inches more than twic
kiruha [24]

The diagonal of a rectangle = sqrt(w^2 + l^2)

w = width

l = length

In this problem,

The diagonal = 20 in

w = x

l = 2x + 8

Let's plug our numbers into the formula above.

20in = sqrt((x)^2 + (2x + 8)^2)

Let's simplify the inside of the sqrt

20 in = sqrt(5x^2 + 32x + 64)

Now, let's square both sides.

400 = 5x^2 + 32x + 64

Subtract 400 from both sides.

0 = 5x^2 + 32x - 336

Factor

0 = (5x - 28)(x + 12)

Set both terms equal to zero and solve.

x + 12 = 0

Subtract 12 from both sides.

x = -12

5x - 28 = 0

Add 28 to both sides.

5x = 28

Divide both sides by 5

x = 28/5

The width cant be a negative number so now we know that the only real solution is 28/5

Let's plug 28/5 into our length equation.

Length = 2(28/5) + 8 = 56/5 + 8 = 96/5

In conclusion,

Length = 96/5 inches

Width = 28/5

4 0
3 years ago
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