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rewona [7]
4 years ago
11

What is 2 times (-2a-7) equal to

Mathematics
2 answers:
Olenka [21]4 years ago
4 0

Answer:

-4a -14

Step-by-step explanation:

2* (-2a-7)

Distribute

2(-2a) - 2(7)

-4a -14

Brilliant_brown [7]4 years ago
4 0

Answer:

-4a - 14

Step-by-step explanation:

Solve by doing distribution.

2 x -2a = -4a

2 x -7 = -14

Input the numbers to get : -4a - 14

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How many terms are in the polynomial abcd + e-n2?<br>two<br>three<br>five<br>six​
ELEN [110]

Answer: There are 3 terms

Step-by-step explanation: You count the abcd as 1 term because it is all multiplied together, the e term is counted as another term, so there are 2 terms, and the n2 term is counted as a term getting you 3 terms in total.

3 0
3 years ago
How do solve for x in 50=-10(x+10)​
Svetllana [295]

Answer:

x=-15

Step-by-step explanation:

50=-10(x+10)

Distribute 10: 50=-10x-100

Add 100 to both sides: 100+50=-10x-100+100

150=-10x

Simplify: 150/-10=-10x/-10

x=-15

4 0
3 years ago
Which number is missing in the table of values below?
Kisachek [45]

Answer:

216

Step-by-step explanation:

Your multipling by 6 /36*6=216

216*6=1,296

4 0
3 years ago
Read 2 more answers
Consider the following system of equations. x + y = 11 2x - 3y = -3 Which equation can be added to the system so the solution do
3241004551 [841]

Answer:

Step-by-step explanation:

We have to find the system in which we can use the x and y from the given system of equations and make it hold true

From the given equations:

x+y = 11\\2x - 3y = -3

multiply top equation by -2 and add them

-2x - 2y = -22\\2x - 3y = -3\\-5y = -25\\y = 5\\x + 5 = 11\\x = 6

so, x = 6, y = 5

A: x-y = 2

6 - 5 = 1, so its not a

B: -2x + 2y = -2

-2(6) + 2(5) = -12 + 10 = -2

B works

just looking at C and D I can tell it doesnt work

So the answer is B

3 0
3 years ago
For patients who have been given a diabetes test, blood-glucose readings are approximately normally distributed with mean 127 mg
zysi [14]

Answer:

Between the lower-bound of 117 mg/dl and the upper bound of 137 mg/dl.

Step-by-step explanation:

Empirical Rule

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Central Limit Theorem:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this question:

Mean of 127, standard deviation of 10.

For the sample mean:

By the Central Limit Theorem, mean is 127, while the standard deviation is s = \frac{10}{\sqrt{4}} = 5

According to the empirical rule, in 95 percent of samples the SAMPLE MEAN blood-glucose level will be between?

By the Empirical Rule, within 2 standard deviations of the mean. So

127 - 2*5 = 117 mg/dl

127 + 2*5 = 137 mg/dl.

Between the lower-bound of 117 mg/dl and the upper bound of 137 mg/dl.

7 0
3 years ago
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