(I'm going to translate y' to dy/dx as it makes it easier to read for me, you could change it back if you wanted.)
(separate the variables)
(by letting c = ln k and using log laws)
(raise everything to power e)
(applying boundary conditions)
Particular solution:
A. Because you would have to subtract C to isolate a by itself
Answer:
The maximum number of wren that could nest in the area based on the number of cholla cacti is:
Step-by-step explanation:
The information provided by the text mentions that each cholla cactus can house a nest in which two adults and a maximum of five young will live (seven in total per nest), so this information can be represented as follows:
- Maximum number of wrens = number of cholla cactus * 7
Since six cholla cacti are counted in the area, this value is replaced in the created equation:
- Maximum number of wrens = 6 * 7
- <u>Maximum number of wrens = 42
</u>
The area could house <u>a maximum of 42 wrens, where 12 would be adults and 30 would be young at most</u>.
Answer:
49
Step-by-step explanation:
Answer:
It gets smaller.
Step-by-step explanation:
You can multiply by 8 to put the equation in the form ...
... b = 48/a
which is the form indicating <em>b</em> is inversely proportional to <em>a</em>. Thus, when <em>a</em> increases, <em>b</em> decreases, and vice versa.
