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Sonja [21]
3 years ago
6

If q is the midpoint of segment PR, find the coordinates of R if P (11,-2) and Q (4,3) ​

Mathematics
1 answer:
Murrr4er [49]3 years ago
3 0

Answer:

  R(-3, 8)

Step-by-step explanation:

R = 2Q -P

R = 2(4, 3) -(11, -2) = (8-11, 6+2)

R = (-3, 8)

_____

You can derive the formula for the endpoint from the formula for the midpoint:

  Q = (R + P)/2

  R = 2Q - P . . . . . . multiply by 2 and subtract P

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How to do 5,745 / 66
lorasvet [3.4K]

Answer:

87.0454545455

Step-by-step explanation: This is hard to explain on this text box. Please go to this https://www.wikihow.com/Do-Long-Division. Remember, always put a decimal point at the end. If you run out of number and you have a number left over. Keep adding zeros to the dividend.  


7 0
4 years ago
HELP ASAP 10 POINTSSS
kiruha [24]

Answer:

Complementary angles, adjacent angles

Step-by-step explanation:

Which relationships describe angles 1 and 2?

Options: Complementary angles, vertical angles, supplementary angles, adjacent angles

Angles 1 and 2 are opposite to the 90° angle. So, the angles' relationship to that angles is a vertical angle, meaning that the two add up to 90°.

Complementary angles add up to 90°, so this option is correct.

Vertical angles are the pairs of opposite angles formed by two intersecting lines. Because the two angles do not follow this definition, this option is incorrect.

Supplementary angles add up to 180°. However, we know that the two add up to 90°, so this option is incorrect.

Adjacent angles are angles that are next to each other, so this option is correct.

I hope this helps! Feel free to ask any questions!

6 0
3 years ago
Find all solutions of the equation in the interval [0,2pi)<br> 8sec^2x+4tan^2x-12=0
andrezito [222]
Π/6+2πk
5π/6+2πk
you need to factor and use trig identities

6 0
3 years ago
Read 2 more answers
QS bisects $\angle PQR$ and $m\angle PQR\ =\ 119\degree$ .
deff fn [24]

Answer:

Step-by-step explanation:

Id QS bisects angle PQR, then <PQS = <SQR and <PQS+<RQS = <PQR

The formula then becomes

<PQS+<PQS = <PQR

2<PQS = <PQR

<PQS = <PQR/2

Given <PQR = 119°

Substitute into the resulting expression above;

<PQS = <PQR/2

<PQS = 119/2

<PQS = 59.5°

Since <RQS = <PQR, hence <RQS is also 59.5°

7 0
3 years ago
What is the length of segment KR?<br><br> A. 3 mm<br> B. 7 mm<br> C. 8.6 mm<br> D. 17.2 mm
marshall27 [118]

Answer:

Option D. KR=17.2\ mm

Step-by-step explanation:

we know that

The Centroid of a Triangle is the center of the triangle that can be calculated as the point of intersection of all the three medians of a triangle. The centroid divides each median in a ratio of 2:1

In this problem the point R represent the centroid of triangle JKL

therefore

KR=(2/3)KM

substitute the value

KR=(2/3)(25.8)=17.2\ mm

3 0
3 years ago
Read 2 more answers
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