Answer:
1500
Explanation:
Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.
The total population size of F2 generation = 2000
The proportion of yellow seeded plants in F2 generation = 3/4 (since the F2 phenotype ratio is given 3 yellow: 1 green)
Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500
Answer:
the male reproductive cell is called a(n) sperm
the female reproductive cell is called a(n) egg
when the male and female cells join during fertilization, a(n) embryo forms
Explanation
During a males life, the sperm forms. During a females life, the egg forms. When a man and a woman fall in love, the reproduce, causing the sperm and egg join to form a embryo
