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vazorg [7]
2 years ago
6

If a disorder limits, the number of calcium ions that can bind to actin, what would happen to the sarcomere?​

Biology
1 answer:
sveticcg [70]2 years ago
5 0

Answer:

Contraction is prevented

Explanation:

The sarcomere is the basic contratile unit of muscle i.e the unit responsible for contraction in the muscle and it consist of two main protein actin; which forms filaments involved in contraction and myosin; a motor protein responsible for contraction. Calcium interacts with these protein and in the absence of Ca, contraction is inhibited (sacromere with not be able to undergo contraction)

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A scientist isolates a gene from a human cell that codes for a specific protein. The gene is inserted into a bacterial plasmid i
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neogi ds, trikha v, mishra kk, bandekar sm, yadav cs. comparative study of single lateral locked plating versus double plating i
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1 year ago
A mutation can cause a defect in human hemoglobin which would result in this type of mutation
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sickle cell disease

8 0
2 years ago
How do living things in an ecosystem interact
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3 years ago
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A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recess
Amanda [17]
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
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And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
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6 0
2 years ago
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