Question

Company XYZ has 97 employees. 31 Of the employees are vegetarian, 36 of the employees owns a Nissan Leaf and 6 of the employees are vegetarian and own a Nissan Leaf. If you randomly select an employee from company XYZ, what is the probability that the employee is vegetarian or that she/he owns a Nissan Leaf?

Answer 1

Answer:  $\dfrac{61}{97}$

Step-by-step explanation:

Let V = Event of selecting vegetarian employee

N =  Event of selecting employee who owns a Nissan Leaf.

Given: Total employees = 97

n(V) = 31

n(N) = 36

n(N and V) = 6

By formula,

n(N or V) = n(V) + n(V) - n(N and V)

= 31+36-6

=61

By probability formula,

$P(N \ or \ V)=\dfrac{n(N\ or\ V)}{Total }\\\\=\dfrac{61}{97}$

Hence, the probability that the employee is vegetarian or that she/he owns a Nissan Leaf =  $\dfrac{61}{97}$