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oksano4ka [1.4K]
3 years ago
7

Kevin runs 7 miles in 50 minutes. At the same rate, how many miles would he run in 75 minutes?

Mathematics
1 answer:
lubasha [3.4K]3 years ago
4 0

Answer:

10.5 miles

Step-by-step explanation:

He runs 7/50 of a mile in 1 minute

In 75 min, he runs (7/50) • 75 = 10.5

He runs 10.5 mi in 75 min

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If the right side of the equation dy dx = f(x, y) can be expressed as a function of the ratio y/x only, then the equation is sai
melomori [17]

Answer:

 y = x*sqrt(Cx - 1)

Step-by-step explanation:

Given:

                                  dy / dx = (x^2 + 5y^2) / 2xy

Find:

Solve the given ODE by using appropriate substitution.

Solution:

- Rewrite the given ODE:

                               dy/dx = 0.5(x/y) + 2.5(y/x)

- use substitution y = x*v(x)

                               dy/dx = v + x*dv/dx

- Combine the two equations:

                                v + x*dv/dx = 0.5*(1/v) + 2.5*v

                                x*dv/dx = 0.5*(1/v) + 1.5*v

                                x*dv/dx = (v^2 + 1) / 2v

-Separate variables:

                                 (2v.dv / (v^2 + 1) = dx / x  

- Integrate both sides:

                                 Ln (v^2 + 1) = Ln(x) + C

                                 v^2 + 1 = Cx

                                 v = sqrt(Cx - 1)

- Back substitution:

                                (y/x) = sqrt(Cx - 1)

                               y = x*sqrt(Cx - 1)

                         

3 0
3 years ago
What is the conclusion of the statement in the box below?
Nady [450]

Answer:

D

Step-by-step explanation:

x²=4

x=√4

X1=2

X2=-2

6 0
3 years ago
A new truck sells for $29,000 and depreciates 12% each year. Find the value of the truck after 10 years.
ozzi

Answer:

according to the question value got less 12% each year

first of all the 12% of 29000$ = 29000÷100×12= 3480 $

in one year truck value deprecates 3480$

in 10 years it will 3480$×10 =34800$

now truck cost will be = 29000-34800$= -5000$

5 0
3 years ago
In the library on a university campus, there is a sign in the elevator that indicates a limit of 16 persons. Furthermore, there
Vedmedyk [2.9K]

Answer:

a) 151lb.

b) 6.25 lb

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

In this problem, we have that:

\mu = 151, \sigma = 25, n = 16

So

a) The expected value of the sample mean of the weights is 151 lb.

(b) What is the standard deviation of the sampling distribution of the sample mean weight?

This is s = \frac{\sigma}{\sqrt{n}} = \frac{25}{\sqrt{16}} = 6.25

8 0
3 years ago
HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! PLZZZZZZZZZ 8PTS!!!!!!!!!!!!!!!!
Harlamova29_29 [7]

Answer:

The first box is c

second box is b

Third box is c

Step-by-step explanation:

6 0
3 years ago
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