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mariarad [96]
3 years ago
13

How to write “6 times the quantity two x plus three y” in a Algebraic expression.

Mathematics
2 answers:
Schach [20]3 years ago
8 0

Answer:

6(2x + 3y)

Step-by-step explanation:

6 × 2x + 6 × 3y

6(2x + 3y)

kolbaska11 [484]3 years ago
6 0
Algebraic expression: 6*2x + 3y
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Ok for one im sooo sooorrry i know how it feels but guess what that guy is probably a loser you should tell yourself your better than him and you deserve better. Some People are just du.mb but u can do better.

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How do you solve this for math -3/4÷(-8/5)
Natasha2012 [34]

Answer:

15/32

Step-by-step explanation:

(-3/4)÷(-8/5)

(-3/4)×(-5/8)

15/32

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4 years ago
5. Consider the system of equation:
liubo4ka [24]

Answer: A

Step-by-step explanation:

7 0
2 years ago
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Bill and his friends went to red robin. Their order consisted of 2 hamburgers to $5.49 each, a chicken sandwich for $6.25, an or
Dvinal [7]

Answer:

47.27

Step-by-step explanation:

5.49+5.49+6.25+12.99+1.75+1.75+1.75+1.75=37.22

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37.22×.07 for tax=2.61

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6 0
3 years ago
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Simplify the square root of 3 times the fifth root of 3.
bogdanovich [222]

Answer:

<h2><em>Three to the three fifths power.</em></h2>

Step-by-step explanation:

The given expression is

\sqrt{3\sqrt[5]{3} }

To simplify this expression, we have to use a specific power property which allow us to transform a root into a power with a fractional exponent, the property states:

\sqrt[n]{x^{m}}=x^{\frac{m}{n}}

Applying the property, we have:

\sqrt{3\sqrt[5]{3}}=\sqrt{3(3)^{\frac{1}{5}}}=(3(3)^{\frac{1}{5}})^{\frac{1}{2}}

Now, we multiply exponents:

(3(3)^{\frac{1}{5}})^{\frac{1}{2}}\\3^{\frac{1}{2}}3^{\frac{1}{10}}

Then, we sum exponents to get the simplest form:

3^{\frac{1}{2}}3^{\frac{1}{10}}=3^{\frac{1}{2}+\frac{1}{10}} =3^{\frac{10+2}{20}}=3^{\frac{12}{20}}  \\\therefore \sqrt{3\sqrt[5]{3}}=3^{\frac{3}{5} }

Therefore, the right answer is <em>three to the three fifths power.</em>

3 0
4 years ago
Read 2 more answers
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