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Lisa [10]
2 years ago
14

How do I find the mean absolute deviation

Mathematics
1 answer:
hjlf2 years ago
7 0
First, you would find the mean of the data. Once you have the number, you would find the difference between the mean and the other numbers. Once you have all of those numbers, you find the mean of that set. For example:
The mean of this set is 9. We then use this number to find the difference between all of the numbers. So 14-9= 5, 9-7=2, 9-6=3, 9-5=4, 13-9=4. Finding the mean of 5, 2, 3, 4, and 4 results in 18/5 or 3.6
3.6 is the mean absolute deviation. 
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Luden [163]
That'd be  3 / (3+1) times 4811 students, or 3608 students who are female.

The other fourth of the students are male.


5 0
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siniylev [52]
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8 0
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Help plz answer quick
Inessa [10]

Answer:

around 1.67 inches

Step-by-step explanation:

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8 0
2 years ago
What is the missing term? (10x-4x^2)-(7x+?)=3x-6x^2
mafiozo [28]
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</span>
6 0
3 years ago
Read 2 more answers
Find the difference quotient <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bf%28x%20%2B%20h%29%20-%20f%28x%29%7D%7Bh%7D" id="TexFor
AlladinOne [14]

Answer:

-2x - h - 3

Step-by-step explanation:

Step 1: Define

Difference Quotient: \frac{f(x+h)-f(x)}{h}

f(x) = -x² - 3x + 1

f(x + h) means that x = (x + h)

f(x) is just the normal function

Step 2: Find difference quotient

  1. <u>Substitute:</u> \frac{[-(x+h)^2-3(x+h)+1]-(-x^2-3x+1)}{h}
  2. <u>Expand and Distribute:</u> \frac{[-(x^2+2hx+h^2)-3x-3h+1]+x^2+3x-1}{h}
  3. <u>Distribute:</u> \frac{-x^2-2hx-h^2-3x-3h+1+x^2+3x-1}{h}
  4. <u>Combine like terms:</u> \frac{-2hx-h^2-3h}{h}
  5. <u>Factor out </u><em><u>h</u></em><u>:</u> \frac{h(-2x-h-3)}{h}
  6. <u>Simplify:</u> -2x - h - 3

8 0
3 years ago
Read 2 more answers
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