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2 years ago

How do I find the mean absolute deviation

Mathematics

1 answer:

hjlf2 years ago

7 0

First, you would find the mean of the data. Once you have the number, you would find the difference between the mean and the other numbers. Once you have all of those numbers, you find the mean of that set. For example:
The mean of this set is 9. We then use this number to find the difference between all of the numbers. So 14-9= 5, 9-7=2, 9-6=3, 9-5=4, 13-9=4. Finding the mean of 5, 2, 3, 4, and 4 results in 18/5 or 3.6
3.6 is the mean absolute deviation.

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2 years ago

Do a and b have the same value in the equations 2(a-1.1)=5.8 and 5/2b-2 3/4=7 1/4

luda_lava [24]

Answer:

Step-by-step explanation:

Solve each equation and compare the solutions

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2 years ago

The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E

Gnoma [55]

Answer:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

Step-by-step explanation:

Given

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$AC = 10$

$AB = 5$

$\angle C = 30^\circ$

$ED = 7.5$

$DF = 25$

$\angle F =30$

$\angle E =90$

Required

Which of the options is/are true:

$\triangle CBA {\displaystyle \sim } \triangle FED$ $\triangle CBA {\displaystyle \sim } \triangle FDE$ $\triangle BAC {\displaystyle \sim } \triangle EFD$

$\triangle BAC {\displaystyle \sim } \triangle EDF$ $\triangle ABC {\displaystyle \sim } \triangle DE\ F$ $\triangle ABC {\displaystyle \sim } \triangle DFE$

The given triangles, implies that:

$A {\displaystyle \sim } \ D$

$B {\displaystyle \sim } \ E$

$C {\displaystyle \sim } \ F$

By taking each sides of both triangle, one after the other; the possible similar triangles are:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

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3 years ago