G^−m ÷ g^n
1st g^−m=1/g^m, hence g^−m ÷ g^n = (1/g^m) /(g^n)==> 1/(g^m)(g^(n)
==> 1/(g^m+n) or g^(-m-n)
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Relative Frequency is how often something happens divided by all outcomes while Experimental probability<span> is the ratio of the number of times an event occurs to the total number of trials or times the activity is performed.</span>
Answer:

Step-by-step explanation:
A compound inequality is an inequality that combines two simple inequalities
we are given that

<u>solving</u><u> </u><u>x </u><u>for</u><u> the</u><u> first</u><u> equation</u><u>:</u>

add 4 to both sides:

divide both sides by 4 and since we are dividing both sides by a positive number the inequality won't swap

<u>solving</u><u> </u><u>x </u><u>for</u><u> the</u><u> </u><u>second</u><u> equation</u><u>:</u>

cancel 5 from both sides:

divide both sides by 9 and since we are dividing both sides by a positive number:

therefore by combining the equations we obtain:

hence,
our answer is A)