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Anon25 [30]
3 years ago
11

1)Find the value of m.4(m - 2) = 24​

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
6 0

Answer:

m = 8

Step-by-step explanation:

4(m - 2) = 24

4m -8 = 24

4m = 32

m = 8

marissa [1.9K]3 years ago
5 0

Answer:

m = 8

Step-by-step explanation:

4 ( m - 2 ) = 24

→ Expand brackets

4 m - 8 = 24

→ Add 8 to both sides

4 m = 32

→ Divide both sides by 4 to isolate m

m = 8

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Ivenika [448]

Answer:

it is 3 i am pretty sure

Step-by-step explanation:

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3 years ago
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Please help me solve this equation and show the work show me how you got the answer
Nesterboy [21]

Answer: k=3

Step-by-step explanation:

To solve for k, you want to isolate k.

\frac{2}{5} (5k+35)-8=12            [add both sides by 8]

\frac{2}{5} (5k+35)=20                  [multiply both sides by 5/2]

5k+35=50                       [subtract both sides by 35]

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7 0
3 years ago
The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds
Bumek [7]
Answer: 11.5% 

Explanation:


Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds. 

Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}
\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}
\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

So, the z-score of 720 seconds is given by:

\text{z-score} = \frac{x - \mu}{\sigma}
\\
\\ \text{z-score} = \frac{720 - 600}{100}
\\
\\ \boxed{\text{z-score} = 1.2}

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) 
\\ = P(z \ \textgreater \  1.2)
\\ = 1 - P(z \leq 1.2)
\\ = 1 - 0.885
\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
8 0
3 years ago
There are 685 Students 80 Percent of them are going on a feild trip how many students are going on the feild trip
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685 students X 0.80 = 548 students going on the field trip.
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Answer:

still need help with this question?

Step-by-step explanation:

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