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3 years ago

I need help on 16 please

Mathematics

1 answer:

jonny [76]3 years ago

5 0

I believe it would be 65

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Find the coordinates of the vertices of the figure after the given transformation. translation: (x, y)→(x - 4, y + 4) A) J'(1, 0

Colt1911 [192]

Answer:

Step-by-step explanation:

6 0

3 years ago

The equation 9(u -2) + 1.5u = 8.25 models the total miles Michael traveled one afternoon while sledding, where u equals

kirill [66]

Answer:

u = 2.5

Step-by-step explanation:

Since you're working with only one variable, you just need to solve for u:

9(u -2) + 1.5u = 8.25

Multiply the parentheses by 9

9u - 18 +1.5u = 8.25

Add the similar values

10.5u = 8.25 + 18

Simplify

10.5u = 26.25

u = 26.25/10.5

u = 2.5

4 0

4 years ago

Read 2 more answers

Solve -14-5y >-64 A. Y<10 B.y>-10 C. Y>10 D.y<-10

amm1812

Hello :D

Answer:

A. $Y$

Step-by-step explanation:

First, you add by 14 both sides of an equation.

-14-5y+14>-64+14

Then, simplify by equation.

-64+14=-50

-5y>-50

Multiply -1 both sides.

(-5y)(-1)<(-50)(-1)

5y<50

Divide by 5 both sides of an equation.

5y/5<50/5

Divide numbers from left to right.

50/5=10

y<10 is the correct answer.

Hope this helps you! :D

6 0

3 years ago

Justify each step. 3•(10•12)=3•(12•10) =(3•12)•10 =36•10 =360

ziro4ka [17]

Answer:

3•(10•12)=3•(12•10) = 360 = True

Step-by-step explanation:

left-hand side Simplify the following:

3×10×12

10×12 = 120:

3×120

3×120 = 360:

Answer: 360

______________________

Right-hand side:

Simplify the following:

3×12×10

Hint: | Multiply 12 and 10 together.

12×10 = 120:

3×120

Hint: | Multiply 3 and 120 together.

3×120 = 360:

Answer: 360

5 0

4 years ago

What is the simple interest on $360 borrowed for 30 months at 12.3%

Alex_Xolod [135]

Keeping in mind that there are 12 months in a year, therefore, 30 months is really 30/12 years,

$\bf ~~~~~~ \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$360\\
r=rate\to 12.3\%\to \frac{12.3}{100}\to &0.123\\
t=years\to \frac{30}{12}\to &\frac{15}{6}
\end{cases}
\\\\\\
I=(360)(0.123)\left( \frac{15}{6} \right)\implies I=110.7$

7 0

4 years ago