Answer:
a. 
b. x = 10
Step-by-step explanation:
a. The number of home runs hit by Jack last season = x
It is given that Henry hit 3 more than half as many home runs as Jack hit.
Half of the runs hit by Jack = 
3 more than half the runs = 
So, the number of home runs hit by Henry = 
But, it is given that Henry hit a total of 8 runs.
Therefore, 
b. 
Subtract 3 from both sides.

= 5
x = 5 × 2
= 10
Hence, Jack hit 10 runs in the last season.
Answer:
70.83% entrants will have distances between 150 and 160.
Step-by-step explanation:
This question is incomplete without an attachment; here is the attachment enclosed with the answer.
From the graph attached,
Number of entrants having distances between 150 and 160 feet = 8 + 9 = 17
Number of entrants between 140 and 200 feet = 8 + 9 + 4 + 2 + 1 = 24
Percent of entrants having distance between 150 and 160 feet = 
= 
= 70.83%
Therefore, 70.83% entrants will have distances between 150 and 160.
Answer:
36
Step-by-step explanation:
I think it may be 36. I did 6×6, but I'm not fully positive
The distance travelled by an object at time t is given by: d = stwhere d is the distance, s is the speed and t is the time.
Given that the cheetah travels a maximum of 70mph, the distance travelled by the cheetah travelling at 70mph at time t is given by d = 70t
There are 60 mins in one hour, so the distance given in miles per minutes is d = 70/60t = 1.167 miles per minutes.
Part B:
Given that t = 10 minutes, the distance covered by the cheetah in 10 minutes is d = 1.167 x 10 = 11.67 miles.
Part C:
If the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes, then the number of minutes the cheetah have traveled in the first 8 minutes is given by
d = 1.167 x 8 = 9.33 miles.
Part D:
If the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes, then the number of minutes the cheetah have traveled in the second 8 minutes is given by
d = 40/60 x 8 = 5.33 miles
Part E:
The distance the cheetah traveled in the first 8 minutes more than in the second 8 minutes is given by
9.33 miles - 5.33 miles = 4 miles.
Part F:
The ratio of the distance travelled in the first 8 minutes to the distance travelled in the next minutes is given by
9.33 : 5.33 = 1.75 : 1.
Therefore, the distance traveled by the cheetah during the first 8 minutes is 1.75 times greater than the distance traveled during the second 8 minutes.