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IrinaVladis [17]

3 years ago

15

Joyce Meadow pays her three workers $160, $470, and $800, respectively, per week. Calculate what Joyce will pay at the end of th

e first quarter for (A) state unemployment and (B) federal unemployment. Assume a state rate of 5.6% and a federal rate of .6%. Base is $7,000.

1 answer:

DochEvi [55]3 years ago

4 0

The answer to your question is A

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Select the correct answer.<br> Which graph best models the inequality?<br> y ≤ -2/5x + 2

vaieri [72.5K]

Answer:

it would look like this

Step-by-step explanation:

4 0

2 years ago

EASY MATH!!! GIVING BRAINLIEST!!!

Harman [31]

120 grams half life at 45 days would be 60 then half life of 60 in another 45 days (90 total) should be 30 grams

8 0

3 years ago

Factor completely. <br> <img src="https://tex.z-dn.net/?f=x%5E%7B8%7D-%5Cfrac%7B1%7D%7B81%7D" id="TexFormula1" title="x^{8}-\fra

Eduardwww [97]

We have 3⁴ = 81, so we can factorize this as a difference of squares twice:

$x^8 - \dfrac1{81} = \left(x^2\right)^4 - \left(\dfrac13\right)^4 \\\\ x^8 - \dfrac1{81} = \left(\left(x^2\right)^2 - \left(\dfrac13\right)^2\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)$

Depending on the precise definition of "completely" in this context, you can go a bit further and factorize $x^2-\frac13$ as yet another difference of squares:

$x^2 - \dfrac13 = x^2 - \left(\dfrac1{\sqrt3}\right)^2 = \left(x-\dfrac1{\sqrt3}\right)\left(x+\dfrac1{\sqrt3}\right)$

And if you're working over the field of complex numbers, you can go even further. For instance,

$x^4 + \dfrac19 = \left(x^2\right)^2 - \left(i\dfrac13\right)^2 = \left(x^2 - i\dfrac13\right) \left(x^2 + i\dfrac13\right)$

But I think you'd be fine stopping at the first result,

$x^8 - \dfrac1{81} = \boxed{\left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)}$

6 0

3 years ago

For every boy in an advanced math course there are 3 girls who are taking the course.

Nutka1998 [239]

Answer:

If 32 students are enrolled in the course, there would be 24 girls.

Step-by-step explanation:

Given that For every boy in an advanced math course there are 3 girls who are taking the course.

It means if there are four students in the class. There would be 3 girls and 1 boy. Thus, 75% of the students are girls.

Given that there are 32 students enrolled in the course.

so

75% of 32 = 75/100 × 32

= 24

Thus, if 32 students are enrolled in the course, there would be 24 girls.

7 0

2 years ago

I need to know how to simplify this equation

ArbitrLikvidat [17]

$\frac{ {3}^{x + 4} - {3}^{2x + 2} }{ {3}^{x - 2} \times {3}^{x + 4} } = \frac{x + 4 - 2x - 2}{(x - 2) \times (x + 4)} = \frac{ - x + 2}{ {x}^{2} + 4x - 2x - 8 } = \frac{ - x + 2}{ {x}^{2} + 2x - 8}$
i could be wrong, was kinda in a rush

4 0

3 years ago