Ask question

Ask question

All categories

3 years ago

11

Ellie baked a round cookie cake for her sister's birthday. The radius of the cookie cake was 6 inches. If Ellie ate 1/4 of the c

ookie cake, about how many square inches did she eat?

1 answer:

beks73 [17]3 years ago

3 0

Answer:

28.26

Step-by-step explanation:

If you find the area by using the eqaution A=pi*raduis*2 you can then divide it by 4

You might be interested in

HELP NOW PLS The ratio of pineapple juice to cranberry juice in a punch

suter [353]

Answer:

7:6

Step-by-step explanation:

I simplified 14:12

5 0

3 years ago

Read 2 more answers

Point KK is located at (5,-4)(5,−4) on the coordinate plane. Point KK is reflected over the xx-axis to create point K'K

Zinaida [17]

Answer:

The ordered pair that describes the location of K' is (5,4).

Step-by-step explanation:

Reflection over the x-axis:

When a point is reflected over the x-axis, it's x-coordinate stays the same, while the signal of the y-coordinate is changed. So

(x,y) -> (x,-y)

In this question:

Point K(5,-4)

Reflection over the x-axis:

(5,-4) -> (5,-(-4)) -> (5,4)

The ordered pair that describes the location of K' is (5,4).

8 0

3 years ago

What is 8 3/4% expressed as a fraction?<br><br><br> 8/100<br><br> 7/80<br><br> 7/40<br><br> 8/25

Lelu [443]

ANSWER:

7 / 80

8 3/4% expressed as a fraction is 7 / 80.

STEP-BY-STEP EXPLANATION:

Write 8 3/4% as a percentage with a decimal:

= 8.75%

Convert 8.75% to a fraction:

= 8.75% ÷ 100

= 8.75 / 100

Make the numerator a whole number by multiplying both the numerator and denominator by a 100:

= ( 8.75 × 100 ) / ( 100 × 100 )

= 875 / 10000

Divide the numerator and denominator in the fraction by their highest common factor ( HCF ):

HCF = 125

THEREFORE:

= ( 875 ÷ 125 ) / ( 10000 ÷ 125 )

= 7 / 80

5 0

3 years ago

The solution to -2(1–4x) = 3x + 8 is <br> a) 6/11<br> b)2<br> c)-10/7<br> d)-2

amm1812

B
x=2 skdkdjjwwoananaanausid

5 0

3 years ago

A tank holds 300 gallons of water and 100 pounds of salt. A saline solution with concentration 1 lb salt/gal is added at a rate

Shkiper50 [21]

The amount of salt in the tank changes with rate according to

$Q'(t)=\left(1\dfrac{\rm lb}{\rm gal}\right)\left(4\dfrac{\rm gal}{\rm min}\right)-\left(\dfrac{Q(t)}{300+(4-1)t}\dfrac{\rm lb}{\rm gal}\right)\left(1\dfrac{\rm gal}{\rm min}\right)$

$\implies Q'+\dfrac Q{300+3t}=4$

which is a linear ODE in $Q(t)$ . Multiplying both sides by $(300+3t)^{1/3}$ gives

$(300+3t)^{1/3}Q'+(300+3t)^{-2/3}Q=4(300+3t)^{1/3}$

so that the left side condenses into the derivative of a product,

$\big((300+3t)^{1/3}Q\big)'=4(300+3t)^{1/3}$

Integrate both sides and solve for $Q(t)$ to get

$(300+3t)^{1/3}Q=(300+3t)^{4/3}+C$

$\implies Q(t)=300+3t+C(300+3t)^{-1/3}$

Given that $Q(0)=100$ , we find

$100=300+C\cdot300^{-1/3}\implies C=-200\cdot300^{1/3}$

and we get the particular solution

$Q(t)=300+3t-200\cdot300^{1/3}(300+3t)^{-1/3}$

$\boxed{Q(t)=300+3t-2\cdot100^{4/3}(100+t)^{-1/3}}$

5 0

3 years ago