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2 years ago

Plz help

Mathematics

1 answer:

dmitriy555 [2]2 years ago

4 0

Answer:

4: riangular prism

3:triangular pryamid

2: retangular prism

1: cube

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Find the area of the triangle base=8cm height= 5cm

mario62 [17]

Area= 1/2 base x height

Area= 1/2 8x5

Area= 40/2

Area= 20cm^2

8 0

3 years ago

Last year, 31 2 acres of strawberry fields produced approximately 14,700 pounds of strawberries. This year the number of acres p

USPshnik [31]

So in 5 acres of land produces 21,000 pounds of strawberries.

Step-by-step explanation:

Step 1:

Last year, $3\frac{1}{2}$ acres i.e 3.5 acres produced 14,700 pounds of strawberries. So we need to determine how many strawberries were produced per acre.

To do this we divide the total number of strawberries produced by the number of acres it was produced in.

The number of strawberries produced per acre $= \frac{14,700}{3.5} = 4,200$ pounds.

Step 2:

To determine the number of strawberries in 5 acres of land, we multiply the number of strawberries per acre by the number of acres.

The number of strawberries produced in 5 acres $= 5(4,200) = 21,000$ pounds.

So in 5 acres of land produces 21,000 pounds of strawberries.

5 0

3 years ago

If i= square root of -1, what is the value of i^3

Ber [7]

Answer:

$- i$

Step-by-step explanation:

Set up equation.

$i {}^{3} = y$

${i}^{2 } \times i = y$

$- 1 \times i = y$

$- i = y$

6 0

3 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$