The wave phenomenon known as "destructive interference".
Answer:
a) 482.5N
b) 17.4N
Explanation:
40 rev/min = 40 * 2π / 60 = 4.2 rad/s
3 rev/min = 3 * 2π / 60 = 0.314 rad/s
The centripetal acceleration that the child is subjected to
![a = \omega^2r](https://tex.z-dn.net/?f=a%20%3D%20%5Comega%5E2r)
And their centripetal force is
![f = ma = m\omega^2r](https://tex.z-dn.net/?f=f%20%3D%20ma%20%3D%20m%5Comega%5E2r)
From here we can plug the number in
(a) ![f_1 = m\omega_1^2r_1 = 22*4.2^2*1.25 = 482.5N](https://tex.z-dn.net/?f=f_1%20%3D%20m%5Comega_1%5E2r_1%20%3D%2022%2A4.2%5E2%2A1.25%20%3D%20482.5N)
(b) ![f_2 = m\omega_2^2r_2 = 22*0.314^2*8 = 17.4N](https://tex.z-dn.net/?f=f_2%20%3D%20m%5Comega_2%5E2r_2%20%3D%2022%2A0.314%5E2%2A8%20%3D%2017.4N)
Answers :
Explanation:
Given that.
First cylinder data
Inertial I₁ = 2.4 kgm²
angular speed ω₁ = 5.8 rad/s.
Second cylinder data
inertia I₂ = 1.3 kgm²
angular speed ω₂ = 7.0 rad/s.
If the cylinders couple so they have the same rotational axis, what is the angular speed of the combination (in rad/s)?
So, the cylinder couple and move together with the same angular speed
Then, using conservation of angular momentum
L(final) = L(initial)
(I₁ + I₂) • ω = I₁•ω₁ + I₂ω₂
(2.4+1.3)•ω = 2.4 × 5.8 + 1.3 × 7
3.7•ω = 23.02
ω = 23.02 / 3.7
ω = 6.22 rad/s
The combine angular speed of the cylinder is 6.22 rad/s
First let us calculate for the angle of inclination using
the sin function,
sin θ = 1 m / 4 m
θ = 14.48°
Then we calculate the work done by the movers using the
formula:
W = Fnet * d
So we must calculate for the value of Fnet first. Fnet is
force due to weight minus the frictional force.
Fnet = m g sinθ – μ m g cosθ
Fnet = 1,500 sin14.48 – 0.2 * 1,500 * cos14.48
Fnet = 84.526 N
So the work exerted is equal to:
W = 84.526 N * 4 m
<span>W = 338.10 J</span>