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2 years ago

What two things must a measurement include?

Physics

2 answers:

astraxan [27]2 years ago

7 0

The number and units. An example would be 3cm or 4kg.

maw [93]2 years ago

3 0

a UNIT ! If I tell you I have a piece of rope that's 17 long, you still have no idea of how far it can reach until I tell you the UNIT. There's a big difference between ropes that are 17 inches, 17 meters, and 17 miles long.

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The sum of the potential energy and the kinetic energy of an object is its thermal energy. _______________ *

Law Incorporation [45]

Answer:

false

Explanation:

8 0

3 years ago

When heat is added to an object, what is happening to the item at the atomic level? (Check all that apply)

3241004551 [841]

Answer:

Explanation:

heat is energy, energy cannot be made or destroyed but transferred

6 0

3 years ago

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Meher is riding a bicycle on a slope. explain the different motions taking place during this time

gtnhenbr [62]

Answer:

Mehar cant ride down the slope

Explanation:

She does not has a bicycle

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2 years ago

How much heat does it take to raise a cup of water (2.34 x 10-4 m3) from 15.0 °C to 75.0 °C?

Allisa [31]

Answer:58600

Explanation:

Trust me it’s correct.

8 0

2 years ago

The kinetic energy of a proton and that of an a-particle are 4 eV and 1 eV,

madam [21]

Answer:

(b) 1:1

Explanation:

1. Formulae:

E = hf

E = h.v/λ

λ = h/(mv)

E = (1/2)mv²

Where:

E = kinetic energy of the particle
λ = de-Broglie wavelength
m = mass of the particle
v = speed of the particle
h = Planck constant

2. Reasoning

An alha particle contains 2 neutrons and 2 protons, thus its mass number is 4.

A proton has mass number 1.

Thus, the relative masses of an alpha particle and a proton are:

$\dfrac{m_\alpha}{m_p}=4$

For the kinetic energies you find:

$\dfrac{E_\alpha}{E_p}=\dfrac{m_\alpha \times v_\alpha^2}{m_p\times v_p^2}$

$\dfrac{1eV}{4eV}=\dfrac{4\times v_\alpha^2}{1\times v_p^2}\\\\\\\dfrac{v_p^2}{v_\alpha^2}=16\\\\\\\dfrac{v_p}{v_\alpha}=4$

Thus:

$\dfrac{m_\alpha}{m_p}=4=\dfrac{v_p}{v__\alpha}$

$m_\alpha v_\alpha=m_pv_p$

From de-Broglie equation, λ = h/(mv)

$\dfrac{\lambda_p}{\lambda_\alpha}=\dfrac{m_\lambda v_\lambda}{m_pv_p}=\dfrac{1}{1}=1:1$

5 0

3 years ago