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kirza4 [7]
3 years ago
10

The electron has the positron as its antiparticle. A True B False

Physics
2 answers:
Sphinxa [80]3 years ago
8 0
The answer would be true
Gelneren [198K]3 years ago
8 0
The answer would be true. So true tbh
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What type of motion occurs when an object spends around and axis without altering its linear position?
exis [7]
Well there has to have a altering linear position
8 0
3 years ago
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You place a light bulb 8 cm in front of a concave mirror. You then move a sheet of paper back and forth in front of the mirror.
Alika [10]

sorry - late reply...just stumbled across tis...hope u can still use it :)


By the mirror equation: 1/di + 1/do = 1/f

<span>
</span>

<span>where di = distance to image = +12cm (+ for real image)</span>


and do = distance to object = +8cm


Substitute and solve for f, the focal length

<span><span>
1/12 + 1/8 = 1/f
</span><span>
1/f = (8 + 12) / 12 * 8 = 20/96
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5 0
4 years ago
when you stir a cup of tea the floating clip collect at the centre of the Cup rather than in the outer Rim why​
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4 0
3 years ago
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A moving roller coaster speeds up with constant acceleration for 2.3\,\text{s}2.3s2, point, 3, start text, s, end text until it
Ad libitum [116K]

Answer:

Δx=(v+v0/2)t

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0

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7 0
3 years ago
Knowing the P is 1110 N, determine the tension in the rope if the frame is in equilibrium. Express your answer in kN to the near
ra1l [238]

Explanation:

It is given that the value of P is 1110 N. And, for pin connection we have only two connections which are A_{x} and A_{y}. Let T be the tension is rope.

So,  \sum F_{y} = 0 and A_{y} - 1110 = 0

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     \sum F_{x} = 0

And,    T - A_{x} = 0

                  T = A_{x}

Also, \sum M_{A} = 0

                1110(0.75 + 0.75 + 0.75) - T(0.5 + 0.1) = 0

                    2497.5 - 0.6T = 0

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Therefore, we can conclude that the tension in the rope if the frame is in equilibrium is 4.16 kN.

3 0
3 years ago
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