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kirza4 [7]
3 years ago
10

The electron has the positron as its antiparticle. A True B False

Physics
2 answers:
Sphinxa [80]3 years ago
8 0
The answer would be true
Gelneren [198K]3 years ago
8 0
The answer would be true. So true tbh
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A tube of mercury with resistivity 9.84 × 10 -7 Ω ∙ m has an electric field inside the column of mercury of magnitude 23 N/C tha
slava [35]

Answer:

The current through the tube is 73.39A.

Explanation:

The relationship between the resistivity \rho, the electric field E, and the current density J is given by

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J = \dfrac{E}{\rho}

Since the current is I = J\cdot A

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I= \dfrac{23N/C}{9.84*10^{-7}\Omega\cdot m } *3.14*10^{-6}m^2

\boxed{I = 73.39A.}

Hence, the current through the mercury tube is 73.39A.

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