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Kipish [7]
3 years ago
11

If x represents the amount Rita earns each week, which expression represents the amount she earns in a year?

Mathematics
2 answers:
irina1246 [14]3 years ago
4 0

Answer:

52*x

Step-by-step explanation:

In order to get the amount she earns in a year, you have to multiply the number of weeks in the year by the amount she earns each week.  The year has approximately 52 weeks, and calling x the amount Rita earns each week; therefore, 52 times x, represents the amount she earns in a year.

iren2701 [21]3 years ago
4 0
If x is what Rita makes in a week and we want to find out what Rita make's in a year. First there are 52 weeks in a year so all we would have to do is multiply 52 times x or 52x. So your answer is answer choice C. 52x.   Hope this helped. :)
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If I have the full price of an item, & the discounted price of the same item, how do I find the discount percentage?
melamori03 [73]

Answer:

Subtract the discount price from the full price. Divide the amount of change by the original price.

Step-by-step explanation:

Example: Original price = $40 Sale price = $30

$40-$30= 10

10/40= 1/4

1/4 = .25 or 25%

5 0
3 years ago
Please help and i will give 200 points next time NEED A ANSWER FAST
Crazy boy [7]

Answer:

I gotchu the answer is 47

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8 0
2 years ago
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On a snowy evening only 2/3 of the registered students in Bob's chess
OLga [1]
18 / 2 = 9 || 9 x 3 = 27. Therefore, 27 students are registered in Bob’s class.
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2 years ago
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hichkok12 [17]
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8 0
3 years ago
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Dustin has a bag of marbles with 4 blue marbles, 4 white marbles, and 3 red marbles.
diamong [38]

Answer:

A.

\dfrac{6}{55}

B.

\dfrac{6}{55}

C.

\dfrac{4}{165}

Step-by-step explanation:

Dustin has a bag of marbles with 4 blue marbles, 4 white marbles, and 3 red marbles. There are 11 marbles in total.

A. The probability that the first marble drawn is blue marble is

\dfrac{4}{11},

the probability that the second marble drawn is red marble is

\dfrac{3}{10}

The probability that the first marble drawn is blue and the second is red is

\dfrac{4}{11}\cdot \dfrac{3}{10}=\dfrac{12}{110}=\dfrac{6}{55}

B. The probability that the first marble drawn is red marble is

\dfrac{3}{11},

the probability that the second marble drawn is white marble is

\dfrac{4}{10}

The probability that the first marble drawn is red and the second is white is

\dfrac{3}{11}\cdot \dfrac{4}{10}=\dfrac{12}{110}=\dfrac{6}{55}

C. The probability that the first marble drawn is blue marble is

\dfrac{4}{11},

the probability that the second marble drawn is blue marble is

\dfrac{3}{10},

the probability that the third marble drawn is blue marble is

\dfrac{2}{9},

The probability that the first, second and third marbles drawn are blue is

\dfrac{4}{11}\cdot \dfrac{3}{10}\cdot \dfrac{2}{9}=\dfrac{24}{990}=\dfrac{4}{165}

8 0
3 years ago
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