substituting the value of x and y in the eqn,
3×-2 - ( 4×-2 + 6×3 )
-6 - (-8 + 18 )
-6 - 10
■ -16
9514 1404 393
Answer:
h ≤ 6 2/3
Step-by-step explanation:
The inequality is presumed to be ...
15h +40 ≤ 140
15h ≤ 100
h ≤ 6 2/3
__
The graph shows h ≥ 0, because the inequality is only reasonable for h ≥ 0.
Solution :
It is given that a company named "Sugary Sweet" wishes to test about the sweet and the flavorful that their participants like the candy.
There are Two levels of the flavor and three levels of sugar.
Thus it is a Two Way ANOVA test.
A two-way ANOVA test is used to test the effect of any two independent variables on the dependent variable.
Answer
225 ml
Step-by-step explanation:
90 ml =2 parts
1 part=45
5 parts= 225
Answer:
The proportion of babies with birth weights of 6 pounds or less is 0.1056 = 10.56%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Average birth weight of babies was 7.5 pounds and the standard deviation was about 1.2 pounds.
This means that
Find the proportion of babies with birth weights of 6 pounds or less.
This is the pvalue of Z when X = 6. So
has a pvalue of 0.1056
The proportion of babies with birth weights of 6 pounds or less is 0.1056 = 10.56%.