Base 10 has the ten digits: {0, 1, 2, 3, 4, 5, 6,7, 8, 9}
Base 11 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A} where A is treated as a single digit number
Base 12 has the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B}
Base 13 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C}
Base 14 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D}
The digit D is the largest single digit of that last set. So the largest 3-digit base 14 integer is DDD which is the final answer
Note: It is similar to how 999 is the largest 3-digit base 10 integer
Answer:
311%
Step-by-step explanation:
The percentage change is calculated as ...
percent change = ((new value) -(old value))/(old value) × 100%
Filling in the numbers, we have ...
percent change = (181.5 -44.2)/44.2 × 100% ≈ 311%
The global area increased by 311% over the interval.
Step-by-step explanation:
the number of pupils are in the lower school
= (1- 1/5 - ¼) × 600
= (20/20 - 4/20 - 5/20)×600
= (11/20) ×600
= 330 pupils
We'll have to assume that interest is charged annually.
interest = i = p*r*t, where p is the initial amount ($25000), r is the annual interest rate as a decimal fraction, and t is the length of time, in years.
Then $2625 = $25000*0.035*t. Solve for t:
$2625
------------ = 0.035t = 0.105. Dividing both sides by 0.035, we get
$25000
t = 3 years (answer)
