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zhenek [66]
3 years ago
9

Se desconoce el número de alumnos que hay en una clase de repostería, cada alumno elaborará una galleta para cada compañero una

para el mimo y tú na para el profesor y sabe que se cocinará 210 galletas en total plantea una ecuación que te permita encontrar el número de alumnos que hay en clase
Mathematics
1 answer:
svetoff [14.1K]3 years ago
7 0

Answer:

nsjsisjsjwisujssjnsmjsjsjsk jdjdjdjdjdjdjdjdjdjjsjsjxjdjdjnwbshxijandbvdjxkwksndndjjxisjsknendjjjxjzjzjwjowi kwhhdiwiqihiwhsiwjjxiwijidwjjwisisiakskdhbdvfhsiiwnwndhidisiwjehhhhhhhhhhhhhhhhhhhsisjwngxxuiajqnwnbdhdkalapoiwurnxkanammxkbsjjsisisowjncnchshauwoskdmfbcucusiwkkfhdhd

Step-by-step explanation:

jsjsjsjsjdjdjdjjdjddjjsksksskskwkjdjsisiwjjsjdbdbhsbsjsjsjjdiwiwiwjwhdnndbdjd

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I really hate to do this again-
babymother [125]

Answer:

Step-by-step explanation:

4 0
2 years ago
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Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 24 feet,
MatroZZZ [7]

The two quadrilaterals are given similar .

In any similar figure sides are in proportion.The second largest side of quadrilateral ABCD is 16 ft .Let the second longest side of quadrilateral EFGH be x ft. These sides will be in proportion to each other .

The second shortest side of quadrilateral EFGH that is GF will be proportional to the third longest side of quadrilateral ABCD that is BC

We can form a proportion with the proportional sides:

\frac{16}{x} =\frac{12}{18}

To solve for x we cross multiply

12x=(16)(18)

12x=288

Dividing both sides by 12 we get

x=24.

The second longest side of quadrilateral EFGH is 24 ft.

6 0
3 years ago
Who is good at the maths/ algebra??
Goryan [66]
8 < 2b
8/2 < b
4 < b

2b + 15 < 5
2b < 5 - 15
2b < -10
b < -10/2
b < -5

answer is : b > 4 or b < -5


3 0
3 years ago
Convert to a mixed number in simplest form 51/13​
Nata [24]

Answer:

3\frac{12}{13}

Step-by-step explanation:

51 / 13 = 3.9231 = 3

51 - (13 x 3) = 12

3\frac{12}{13}

5 0
3 years ago
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Answer to this question?
Readme [11.4K]
A midsegment is given by the formula:
\frac{x1+x2}{2} , \frac{y1+y2}{2}

Where x1, x2, y1, and y2 correspond to their respective coordinates. We can do the equation:

\frac{-3+5}{2} , \frac{-1+3}{2}
This gets us a midpoint coordinate of <span>(1,1)

</span>As for distance, it will be found by doing:
\sqrt{(x2-x1)^2+(y2-y1)^2}
We can do the following:

\sqrt{(5-(-3))^2+(3-(-1))^2}
\sqrt{(8)^2+(4)^2}
\sqrt{64+16}
This simplifies to 4 \sqrt{5}

:)
5 0
3 years ago
Read 2 more answers
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