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beks73 [17]
3 years ago
7

What is the value of a?

Mathematics
1 answer:
Kisachek [45]3 years ago
5 0
The answer is 41.41
Since we know the side that is opposite to a, and the hypotenuse, we have enough information to get the cosine of a. The cosine is 45/60. If we know the cosine of an angle, we can get the arccos of that value to get the angle. The arccos of 45/60 is about 41.41.

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3 years ago
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Which table represents a function that does not have a constant rate of change ?
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Answer:

I believe D.

Step-by-step explanation:

All the other tables increase at a stady rate but D doesn't.

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3 years ago
Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent
goblinko [34]

Answer:

y(x)=x^2+5x

Step-by-step explanation:

Given: y'=\sqrt{4y+25}

Initial value: y(1)=6

Let y'=\dfrac{dy}{dx}

\dfrac{dy}{dx}=\sqrt{4y+25}

Variable separable

\dfrac{dy}{\sqrt{4y+25}}=dx

Integrate both sides

\int \dfrac{dy}{\sqrt{4y+25}}=\int dx

\sqrt{4y+25}=2x+C

Initial condition, y(1)=6

\sqrt{4\cdot 6+25}=2\cdot 1+C

C=5

Put C into equation

Solution:

\sqrt{4y+25}=2x+5

or

4y+25=(2x+5)^2

y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}

y(x)=x^2+5x

Hence, The solution is y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4} or y(x)=x^2+5x

4 0
3 years ago
A contractor is installing tiles on a floor that measures 132 x 216 inches. If each tile measures 4 x 4 inches, how many tiles w
Kay [80]

Answer:

1782 tiles

Step-by-step explanation:

Given that:

Dimension fo floor = 132 x 216 inches

Area of floor = 132 * 216 = 28512 in²

Dimension of tiles = 4 * 4 inches

Area of tiles = 4 * 4 = 16 in²

Number of tiles needed to cover floor :

Area of floor / Area of tiles

28512 in² / 16 in²

= 1782 tiles

5 0
2 years ago
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