Ask question

Ask question

All categories

3 years ago

7

What is the value of a?

1 answer:

Kisachek [45]3 years ago

5 0

The answer is 41.41
Since we know the side that is opposite to a, and the hypotenuse, we have enough information to get the cosine of a. The cosine is 45/60. If we know the cosine of an angle, we can get the arccos of that value to get the angle. The arccos of 45/60 is about 41.41.

You might be interested in

Suppose a student reaches in the bag and randomly selects nine red chips and eleven yellow chips. Based on this sample, what is

Marysya12 [62]

The good estimate would be 9/20 and 11/20=20/20

3 0

3 years ago

Read 2 more answers

Which table represents a function that does not have a constant rate of change ?

EleoNora [17]

Answer:

I believe D.

Step-by-step explanation:

All the other tables increase at a stady rate but D doesn't.

4 0

3 years ago

Read 2 more answers

I do not understand if anyone could help in steps or anything thank you. Solve for A -2(a + 7) = -9

Ne4ueva [31]

<h2>... Answer is in the pictures above... </h2><h3>... Hope this will help... </h3>

4 0

3 years ago

Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent

goblinko [34]

Answer:

$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

$\int \dfrac{dy}{\sqrt{4y+25}}=\int dx$

$\sqrt{4y+25}=2x+C$

Initial condition, y(1)=6

$\sqrt{4\cdot 6+25}=2\cdot 1+C$

$C=5$

Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

or

$4y+25=(2x+5)^2$

$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

$y(x)=x^2+5x$

Hence, The solution is $y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$ or $y(x)=x^2+5x$

4 0

3 years ago

A contractor is installing tiles on a floor that measures 132 x 216 inches. If each tile measures 4 x 4 inches, how many tiles w

Kay [80]

Answer:

1782 tiles

Step-by-step explanation:

Given that:

Dimension fo floor = 132 x 216 inches

Area of floor = 132 * 216 = 28512 in²

Dimension of tiles = 4 * 4 inches

Area of tiles = 4 * 4 = 16 in²

Number of tiles needed to cover floor :

Area of floor / Area of tiles

28512 in² / 16 in²

= 1782 tiles

5 0

2 years ago