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liraira [26]
4 years ago
6

Find the number that must be added to each expression to form a perfect square trinomial. Then write the trinomial as a binomial

squared.
x^2-24x+____

( )^2
Mathematics
2 answers:
Korvikt [17]4 years ago
8 0

Answer:

-12 is number that is when added to given expression to form perfect square.


Step-by-step explanation:

Given expression is :

x²-24x + _____

We have to make above expression complete square.

We use following formula to complete this question.

a²+2ab+b² = (a+b)²

Comparing given expression to above formula ,we get

a² = x² ⇒ a = x

2ab = -24x

2ab = 2(x)(-12)

hence, the value of b is -12.

Putting the value of b in above formula,we get

(x)²+2(x)(-12)+(-12)² = x²-24x+144

(x-12)² = x²-24x+144

Hence, the trinomial x²-24x+144 is square of binomial (x-12).



uysha [10]4 years ago
6 0

Answer:

Thus, when 144 is added to the given expression x^2-24x+144 to form a perfect square trinomial of (x-12)^2

Step-by-step explanation:

We are given an expression x^2-24x+\_\_

We have find the number such that expression form a perfect square trinomial.

Using identity (a-b)^2=a^2+b^2-2ab

Comparing the above identity with the given expression,

We get a^2=x^2 \rightarrow a=x and -2ab=-24x

-2ab=-24x \Rightarrow ab=12x

Thus, b = 12

and b^{2}=144

Thus, when 144 is added to the given expression x^2-24x+144 to form a perfect square trinomial of (x-12)^2





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Fine -4A+6B (Picture provided)
Ratling [72]

Answer:

Option a

-4A+6B=\left(\begin{array}{ccc}-22&30&32\\-16&-78&48\\42&24&30\end{array}\right)

Step-by-step explanation:

First multiply matrix A by -4.

Then multiply the matrix B by 6.

When multiplying a matrix by a number x you must multiply each element of the matrix by x.

Then we perform operation -4A

-4\left(\begin{array}{ccc}-2&6&1\\1&9&-6\\-9&9&-9\end{array}\right)=\left(\begin{array}{ccc}8&-24&-4\\-4&-36&24\\36&-36&36\end{array}\right)

Now we perform operation 6B

6\left(\begin{array}{ccc}-5&9&6\\-2&-7&4\\1&10&-1\end{array}\right)=\left(\begin{array}{ccc}-30&54&36\\-12&-42&24\\6&60&-6\end{array}\right)

Now we add the resulting matrices

\left(\begin{array}{ccc}8&-24&-4\\-4&-36&24\\36&-36&36\end{array}\right)+\left(\begin{array}{ccc}-30&54&36\\-12&-42&24\\6&60&-6\end{array}\right)=\left(\begin{array}{ccc}-22&30&32\\-16&-78&48\\42&24&30\end{array}\right)

6 0
4 years ago
5. f(x) = x ^ 3 + p * x ^ 2 + qx + 6 (a) Find the value of each constants p and q, given that (x - 1) is a factor of f(x) and wh
lara31 [8.8K]

Answer:

\boxed{\textsf{ The value of p is \textbf{-2} and the value of q is \textbf{ -5}.}}

Step-by-step explanation:

A polynomial is given to us and we need to find the value of the constants in the given equation . The given polynomial to us is :-

\sf\implies f(x)= x^3+px^2+qx + 6

It's mentioned that (x - 1) is a factor of f(x) . This means on putting x = 1 in the given polynomial the value of the polynomial becomes 0 .

<u>Puttting</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>1</u><u> </u><u>in</u><u> </u><u>f</u><u>(</u><u>x</u><u>)</u><u> </u><u>:</u><u>-</u>

\sf\implies f(x)= x^3+px^2+qx + 6 \\\\\sf\implies f(1) = 1^3 + p(1)^2+q(1) + 6 = 0 \\\\\sf\implies f(1)= 1+p + q + 6 = 0 \\\\\sf\implies \boxed{ \red{\sf p + q = -7 }}

\rule{200}2

Now secondly it's given that on dividing the given polynomial by (x + 1) , the remainder is 8 . This means that on putting x = -1 the value of the given polynomial becomes 8 .

<u>Putt</u><u>ting</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>:</u><u>-</u>

\sf\implies f(x)= x^3+px^2+qx + 6 \\\\\sf\implies f(-1) = (-1)^3 + p(-1)^2+q(-1)+6 = 8 \\\\\sf\implies f(-1)= -1+p -q + 6 = 8 \\\\\sf\implies p - q = 8 -6 +1 \\\\\sf\implies  \boxed{ \red{\sf p - q = 3 }}

\rule{200}2

<u>Adding</u><u> </u><u>the</u><u> </u><u>above</u><u> </u><u>two</u><u> </u><u>equations</u><u> </u><u>:</u><u>-</u>

\sf\implies p + q + p - q = -7 + 3 \\\\\sf\implies 2p = -4 \\\\\sf\implies p =\dfrac{-4}{2}\\\\\sf\implies \boxed{\pink{\frak{ p = (-2) }}}

\rule{200}2

<u>Put</u><u> </u><u>this</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>p</u><u> </u><u>in</u><u> </u><u>equation</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>.</u>

\sf\implies p + q = -7 \\\\\sf\implies  -2 + q = -7 \\\\\sf\implies q = -7+2 \\\\\sf\implies \boxed{\pink{\frak{ q = (-5) }}}

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