That would be 8.235*10^-4
3x + 7y = 7
7y = -3x + 7
y = -3/7x + 1
slope = -3/7 (so ur line is decreasing)
y int.....line crosses y axis at (0,1)
x int...line crosses x axis at (7/3,0)....for graphing purposes, 7/3 = 2 1/3
so start at (0,1).....go down 3 and to the right 7, and u will notice that ur line will cross the x axis at (7/3,0)
Answer:
![ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}](https://tex.z-dn.net/?f=%20ME%3D%20z_%7B%5Calpha%2F2%7D%20%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D)
And replacing we got:
![ME= 1.96 *\sqrt{\frac{0.37 (1-0.37)}{480}}= 0.0432](https://tex.z-dn.net/?f=%20ME%3D%201.96%20%2A%5Csqrt%7B%5Cfrac%7B0.37%20%281-0.37%29%7D%7B480%7D%7D%3D%200.0432)
And replacing into the confidence interval formula we got:
And the 95% confidence interval would be given (0.327;0.413).
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Solution to the problem
The confidence interval would be given by this formula
Assuming a 95% of confidence. For the 95% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the normal standard distribution.
The margin of error would be:
![ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}](https://tex.z-dn.net/?f=%20ME%3D%20z_%7B%5Calpha%2F2%7D%20%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D)
And replacing we got:
![ME= 1.96 *\sqrt{\frac{0.37 (1-0.37)}{480}}= 0.0432](https://tex.z-dn.net/?f=%20ME%3D%201.96%20%2A%5Csqrt%7B%5Cfrac%7B0.37%20%281-0.37%29%7D%7B480%7D%7D%3D%200.0432)
And replacing into the confidence interval formula we got:
And the 95% confidence interval would be given (0.327;0.413).
We want to know when h is equal to 0. This represents when the height is 0 and thus, hits the ground.
Then, 0 = 70t - 5t²
0 = 5t² - 70t
0 = 5t(t - 14)
t = 0 and 14.
So, at t = 0, the initial height is 0 and it hits the ground again after 14 seconds.
Answer: C - 18cm
Explanation: