$log(2) = a \: log(3) = b \: \: \\ log(216) = log(2 \times 2 \times 2 \times 3 \times 3 \times 3) \\ = log( {2}^{3} \times {3}^{3} ) \\ = log(2^{3} ) + log( {3}^{3} ) \\ = 3 log(2) + 3 log(3) \\ = 3(a) + 3(b) \\ = 3(a + b) \\ \\ log(216) = 3(a + b)$

8 0

2 years ago

7/8+ -7/16 ÷ 8/10 -1/4

larisa [96]

Answer:

5/64

Step-by-step explanation:

used calculator

4 0

3 years ago

WILL GIVE BRAINLIEST (Right angle) Trigonometry <br> please help!

nirvana33 [79]

Answer:

<A = 41.4°

Step-by-step explanation:

Recall, SOH CAH TOA

Reference angle = <A

Hypotenuse length = 8

Adjacent length = 6

Since Hypotenuse and Adjacent are involved, we would apply CAH, which is:

Cos A = Adj/Hyp

Plug in the values

Cos A = 6/8

Cos A = 0.75

$A = Cos^{-1}(0.75)$

A = 41.4096221° ≈ 41.4° (nearest tenth)

8 0

3 years ago

(1-sin^2x) (1+tan^2x)=1

Sphinxa [80]

$\tt (1 - sin ^2x)\times(1+tan^2x) = 1$

L.H.S

$\tt cos^2x \times sec^2x$

$\tt cos^2x \times \frac{1}{cos^2x}$

$\tt \cancel{ cos^2x} \times\cancel{ \frac{1}{cos^2x}}$

$\tt 1$

R.H.S

Hence proved

5 0

2 years ago

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