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3 years ago

5

Write a rule for a transformation

1 answer:

lys-0071 [83]3 years ago

6 0

Over the x-axis: (x, y)  (x, –y)
Over the y-axis: (x, y)  (–x, y)
Over the line y = x: (x, y)  (y, x)
Through the origin: (x, y)  (–x, –y)

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Dovator [93]

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3 years ago

Read 2 more answers

Determine whether the graph table or equation represents a linear or nonlinear function explain

Anna [14]

<h3>Answer: Linear</h3>

Each time x goes up by 3, y goes up by 2. The rate of change is constant.

slope = (change in y)/(change in x) = 2/3

y intercept = 6 since this is where x = 0

The equation of this line is y = (2/3)x+6

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3 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

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Which additional information is needed to solve this story problem? The zoo had 3 baby pandas in 2006 and gave 2 of them to othe

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Step-by-step explanation:

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3 years ago

Calculate the quotient. If needed, draw a model. 3/4 divided by 1/5

a_sh-v [17]

Answer:

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Step-by-step explanation:

all i really did was plug it into the calculator like so: (3/4)/(1/5) and thats what came out

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3 years ago