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butalik [34]
3 years ago
5

Write a rule for a transformation

Mathematics
1 answer:
lys-0071 [83]3 years ago
6 0
Over the x-axis: (x, y)  (x, –y)
Over the y-axis: (x, y)  (–x, y)
Over the line y = x: (x, y)  (y, x)
Through the origin: (x, y)  (–x, –y)
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To solve 6x=72 do you use the addition property of equality
lawyer [7]

Answer:

No , the division property of equality.

Step-by-step explanation:

The Division Property of Equality states that if you divide both sides of an equation by the same nonzero number, the sides remain equal.

Hope this helps!!

3 0
3 years ago
What is the 7th letter of the alphabet?
docker41 [41]

The seventh letter of the alphabet is G.

Example

A(1) B(2) C(3) D(4) E(5) F(6) G(7)

4 0
3 years ago
Read 2 more answers
*^%Brainliest 15 pounds Question 5 (2 points)
galben [10]

Answer:

0

Step-by-step explanation:

Separate into two parts

\frac{4xy^{3} }{2xy^{2} }  +  \frac{8x^{2} {y}^{5} }{2x {y}^{2} }

Simplify:

This is for the first fraction

\frac{4x {y}^{3} }{2x {y}^{2} }  = (4 \div 2)(x \div x)( {y}^{3}  \div  {y}^{2} )

2(1)( {y}^{3 - 2} )

2{y}

Now for the second fraction:

\frac{8 {x}^{2} {y}^{3}  }{2x {y}^{2} }  = ( 8 \div 2)( {x}^{2}  \div x)( {y}^{5}   \div   {y}^{2} )

4( {x}^{2 - 1} )( {y}^{5 - 2} )

4x {y}^{3}

Add both parts together

2y + 4x {y}^{3}

To turn this into the said formula, that would become:

2 {x}^{0}  {y}^{1}  + 4 {x}^{1}  {y}^{3}

Where:

a=0

b=1

c=1

d=3

Any value with an exponent 0 except zero will be equal to 1

4 0
3 years ago
Help math sucks THESE MAKE MY BRAIN DIE​
Flura [38]

Answer:

A ∩ B = {1, 3, 5}

A - B = {2, 4}

Step-by-step explanation:

The given problem regards sets and set notation, a set can simply be defined as a collection of values. One is given the following information:

A = {1, 2, 3, 4, 5}

B = {1, 3, 5, 6, 9}

One is asked to find the following:

A ∩ B,

A - B

1. Solving problem 1

A ∩ B,

The symbol (∩) in set notation refers to the intersection between the two sets. It essentially asks one to find all of the terms that two sets have in common. The given sets (A) and (B) have the values ({1, 3, 5}) in common thus, the following statement can be made,

A ∩ B = {1, 3, 5}

2. Solving problem 2

A - B

Subtracting two sets is essentially taking one set, and removing the values that are shared in common with the other set. Sets (A) and (B) have the following values in common ({1, 3, 5}). Thus, when doing (A - B), one will omit the values ({1, 3, 5}) from set (A).

A - B = {2, 4}

3 0
3 years ago
Sixteen more than twice a number,m, is 36. write an equation and solve to find the number.
Dimas [21]
32m=36
m=36/32
m=9/8
that's the correct answer
3 0
3 years ago
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